Question

= The figure below shows five resistors and two batteries connected in a circuit. What are the currents 11, 12, and 13? (Consider the following values: R1 1.2012, R2 = 2.08 12, R3 = 3.11 12, R4 = 4.04 N, R5 = 6.16 1. Due to the nature of this problem, do not use rounded intermediate values in your calculations—including answers submitted in WebAssign. Indicate the direction with the sign of your answer.) 1.2970 x 11 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. A 1.7137 12 Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. A 13 -0.0103 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. A = = RS + 12.0V R3 13 11 R2 9.00 V R4 12 R

1

Answer 1

R = 1.200. R2 = 2.088. Po 3.lis R4 a 4.04 R Rs = 6.16.n. KUL in Mesh ® 122 RE Z Za syn z gu *12+ RSI, & Pz I, at R2 2320 Rak 22 RI

6.16 + 3-11T, f 2.08.1? 12 G. 27 I, e 9. 0812 E12 LO Loop ☺ we alle Apply KUL in CR, tha) I g - (1.20+ 4.04 ) I 2 R2 7 3 = 0 71 2.08 1 9 a 5:24 I 2 = 2:08 I? E 9 from kirchoff's junction rule we have It Iz-13 a Ciri on solving there. three we get equahong

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