Homework Answers
Answer
It must be parallel to magnetic field.
Explanation
To apply force on current carrying wire magnetic field must be perpendicular to direction of current.
When magnetic field is parallel to direction of current then no force is applied on wire
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A straight length of current-carrying wire is in a uniform magnetic field. If the wire does...
A straight length of current-carrying wire is in a uniform magnetic field. If the wire does...
A straight length of current-carrying wire is in a uniform magnetic field. If the wire does not experience a force: It must be parallel to the magnetic field. It must be perpendicular to the magnetic field. Everything is as it should be. We have an impossible situation! The wire must be part of a short circuit!
Question 1 2 pts How will the magnetic domains in an unmagnetized "soft" iron rod respond...
Question 1 2 pts How will the magnetic domains in an unmagnetized "soft" iron rod respond to the presence of a strong external magnetic field? The domains will tend to align with the external field. The domains will split into monopoles. The domains will tend to orient themselves perpendicular to the external field, The domains will tend to align so as to cancel out the extemalfiel The domains will not respond to an external magnetic field 2 pts Question 3...
The size of the magnetic force on a straight wire of length L carrying current I...
The size of the magnetic force on a straight wire of length
L carrying current I in a uniform magnetic field
with strength B is
F=ILBsin(?).
Here ? is the angle between the direction of the
current (along the wire) and the direction of the magnetic field.
Hence Bsin(?) refers to the component of the
magnetic field that is perpendicular to the wire, B?. Thus
this equation can also be written as
F=ILB?.
The direction of the magnetic force on...
A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field. If...
A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field. If the current is 15.0 A and it is determined that there is a magnetic force of 2.3 N on the wire due to the interaction of the current and field, what is the magnitude of the magnetic field? A. 0.52 T OB. 0.46 T: C.0.38 T, OD.0.29 T: E.0.18 T: OF. 0.12 T.
Within a uniform magnetic field B, a straight wire is carrying current in the direction shown...
Within a uniform magnetic field B, a straight wire is carrying current in the direction shown in this figure. The direction of this uniform magnetic field is denoted by the blue dots. (Think about what these dots means. This was taught in my lectures.) B. What is the direction of the magnetic force acting on this current-carrying wire? The magnetic force points: A to the right: B. out of the page; C. Into the page: D. to the left; O...
A straight horizontal wire of length 5m is in a uniform magnetic field which has a...
A straight horizontal wire of length 5m is in a uniform magnetic field which has a magnetic flux density of 120mT. The wire is perpendicular to the field lines which act due North. When the wire conducts a current of 14A from East to West calculate the magnitude and direction of the force on the wire.
#12 uniform magnetic field of strength (2T). Find the magnitude of the force on the wire....
#12
uniform magnetic field of strength (2T). Find the magnitude of the force on the wire. Answer in units of N 008 (part 1 of 2) 10.0 points A 10 A current is directed along the post- tive s-axis and perpendicularly to a uniform magnetic field. The conductor experiences a magnetic force per unit length of 0.19 N/min the negative y direction Calculate the magnitude of the magnetic field in the region through which the current 012 10.0 points Consider...
a) A wire carrying a current I is perpendicular to a magnetic field of strength B....
a) A wire carrying a current I is perpendicular to a magnetic field of strength B. Assuming a fixed length of wire, which of the following changes will result in decreasing the force on the wire by a factor of two? Select all correct answers - Decreas the current in th e wire to I/2 - Decrease the field strength to B/2 - Decrease the angle from 90 to 45 degrees - Decrease the angle form 90 to 30 degrees...
A straight wire of length / carrying current / crosses a region of the space with...
A straight wire of length / carrying current / crosses a region of the space with uniform magnetie field B. The force exerted on the wire is F. Find the angle between the wire and the force mies of the magnetic field. A doughnut coil of a square cross-section has two windings with numbers of turns Ni and N2 made one on top of another. The inner and outer radiuses of the doughnut are a and b, respectively. Find the...
7. (5 points) The force exerted by a constant uniform magnetic field on a current-carrying wire...
7. (5 points) The force exerted by a constant uniform magnetic field on a current-carrying wire of length L produces a force per unit length of Fi on the wire. If a wire twice as long and carrying the same current is placed in the same fiel with the same orientation, the force per unit length would be (b) FL (a) 2F (c) FL/2
A straight length of current-carrying wire is in a uniform magnetic field. If the wire does not experience a force: It must be parallel to the magnetic field. It must be perpendicular to the magnetic field. Everything is as it should be. We have an impossible situation! The wire must be part of a short circuit!
Question 1 2 pts How will the magnetic domains in an unmagnetized "soft" iron rod respond to the presence of a strong external magnetic field? The domains will tend to align with the external field. The domains will split into monopoles. The domains will tend to orient themselves perpendicular to the external field, The domains will tend to align so as to cancel out the extemalfiel The domains will not respond to an external magnetic field 2 pts Question 3...
The size of the magnetic force on a straight wire of length
L carrying current I in a uniform magnetic field
with strength B is
F=ILBsin(?).
Here ? is the angle between the direction of the
current (along the wire) and the direction of the magnetic field.
Hence Bsin(?) refers to the component of the
magnetic field that is perpendicular to the wire, B?. Thus
this equation can also be written as
F=ILB?.
The direction of the magnetic force on...
A current-carrying wire of length 52.0 cm is positioned perpendicular to a uniform magnetic field. If the current is 15.0 A and it is determined that there is a magnetic force of 2.3 N on the wire due to the interaction of the current and field, what is the magnitude of the magnetic field? A. 0.52 T OB. 0.46 T: C.0.38 T, OD.0.29 T: E.0.18 T: OF. 0.12 T.
Within a uniform magnetic field B, a straight wire is carrying current in the direction shown in this figure. The direction of this uniform magnetic field is denoted by the blue dots. (Think about what these dots means. This was taught in my lectures.) B. What is the direction of the magnetic force acting on this current-carrying wire? The magnetic force points: A to the right: B. out of the page; C. Into the page: D. to the left; O...
#12
uniform magnetic field of strength (2T). Find the magnitude of the force on the wire. Answer in units of N 008 (part 1 of 2) 10.0 points A 10 A current is directed along the post- tive s-axis and perpendicularly to a uniform magnetic field. The conductor experiences a magnetic force per unit length of 0.19 N/min the negative y direction Calculate the magnitude of the magnetic field in the region through which the current 012 10.0 points Consider...
A straight wire of length / carrying current / crosses a region of the space with uniform magnetie field B. The force exerted on the wire is F. Find the angle between the wire and the force mies of the magnetic field. A doughnut coil of a square cross-section has two windings with numbers of turns Ni and N2 made one on top of another. The inner and outer radiuses of the doughnut are a and b, respectively. Find the...
7. (5 points) The force exerted by a constant uniform magnetic field on a current-carrying wire of length L produces a force per unit length of Fi on the wire. If a wire twice as long and carrying the same current is placed in the same fiel with the same orientation, the force per unit length would be (b) FL (a) 2F (c) FL/2
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