Question

Solve for the velocity at point B in m/s. You may assume point A is moving in the -y direction and point B moves in the x-direction. у AC 0.2m - TB/A VA = 2 m/s 45° ω B NB

Answer 1

Solution-

As per the given question, two velocities are acting in x and y direction at a distance 0.2 m from each other.

Let us suppose the instantaneous centre of rotation be C.

As shown in figure below-

JOE I IC 45 en NBA 0.2m W VA = 2 m/s VR B

Now,

Angular velocity about instantaneous centre of rotation is w = v_A​​​​​​(AC)= v_B(BC) ...(1)

Since v_A = 2 m/s , AC = 0.2cos(45°) = 0.2/√2 and

BC = 0.2sin(45°) = 0.2/√2

On putting these values in equation (1), we get

v_A(AC) = v_B(BC)

2(0.2/√2) = v_B(0.2/√2)

Or 2 = v_B

Or v_B = 2 m/s

Hence, the velocity at point B is v_B = 2 m/s in x-direction.