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In the worst case, the very best that a comparison based sorting algorithm can do when sorting n records is Q (n^2) Q(log (n!


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Answer #1

In the worst case scenario, we will have n elements to be compared and this will take n number of iterations

Leading to a complexity of n^2 as n*n comparisons will be made in the worst case due to execution of 2 loops

So, correct ans is option A

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