Question

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this question has two parts

small bob is attached to a cord of length 12 m and is released from rest when 5. Take = 0.20 m 1.2 m С BA 4. Determine the time required for the bob to return to point A. (Round the final answer to three decimal places.) The time required for the bob to return to point AS - S

Answer 1

please see the corrected ans

- 2.8592 radls wn 1.2 - = 2.1975 sec 1:03 25 sol2 of the As pendulush moves.bet A & B then length pendulus is talab = 1.2m. Who 9 9.8) LAB Z RI 2T wat 2.8592 The falling from A to B is one quarter periods TAB=Ž 2, = 0.54938 sec As pend celem moves bern B&C, the length of pendulugn Is dalBC = 1:2-0.2 = 1m 9 9,81 3.132 m aradis wnz Wn2 = TBC 211 Za = 2.006 see Tona 3-132 The motion from B to C & back to B is one half period. TBcb = {xde = 1,003 see As the pendulum moree from B Tof, the length rragcan-1.2m - TBA= 2,50-56938 see @ Time required to return to A; Z=ZABT ZB CBT EBA =0.54938 + 110037 0154938 Z = 2.162 sec Om - OA for falling, forum A to B, ÖB óm = Wne x QA VB=locês = lab wnexca LAB Whioa for rising foom B toe, og = VB omar TBC O c-max 1-2*9.8592 % 5° IBC con | X3.132 Oc = 5.490° Ans frnal Ars @ time read to retum to a the amplitude Oca 5.480° At Bi IBC max LAB UniOA may Wnz (2-10 2gece