Question

Zm

Exercise 6.1.26 Your answer is partially correct. Try again. An aluminum wire d = 2 mm in diameter is bent into the confirmation shown below. Determine the mass m and the location of the center of mass (X, YM, ZM) of the configuration. Assume R= 270 mm, h = 140 mm. Material is homogeneous with a constant density p= 2690 kg/m3. Cross sectional area is constant in all regions. R у h m = .0127 kg XM = 291.5 mm YM 96.68 mm ZM 73.95 mm Click if you would lilca

Answer 1

Date B Bep 0 AB DA 3 Z- Coordinate of z = h = 140 mm z = b = 7o mm centre each segment 0 mm length of each segment 4 - TR طعا mass of each segment m = (P) (2 d 2 L) dep) (VR) m₂ = (P) (17 2²4) = ( 77 d²p) (b) m2 = (4) (1 22 23) q A boay q eshire configuration is 44d2p) (28) Now Z- coordinate Centre m, z + m₂ Zztmz z Zma Zmiz Emi mitm tm. lg de) Car) (h) +42p) (6) (%) (942P) (28) (0) to 229) (AR) + (Aps(h) + (7 4 d² 1) (2R) TRL + 6% to */270) (140) + 140% (TR+ht 2R) A1270) 1404 21270) Zma 84. 12 mm Ang