Question

Problem 4 (20pts). A transformer with N1, N3 turns at the input and N2, N4 turns at the output is wrapped as drawn. The magnetic flux in the core is given as Q = -20sin(wt) (Wb), and Ry = 1k1. Find: a) V2, V3 and 12, 13. b) Direction of I2, I3. c) What is Rin? N2=600 N2=300 Nz=100 N4=300 1 12 Iz Rin RL WW V V2 V3 Ri=100012

Answer 1

Nico N₂ = 300 N3 Ny = 30 . Rin} VO Vz V3 given $ -20 sin(wt) & Ri=lku from faroday's 's law mortage indirent a nad then V2 , Ne do वन = 200 x 1 06-20 80lw?) = - 300 x row costot) Vg -6000w cos (64) Yh+70) soo melog det fa f= 6oHz (Eroq uning of their yetem) angular frequsring ' from the transformer and where به کم

(het zal sorg.mhga 2 (uttalso mol تم کو Ig sh IN Iz yn NE I Iq Noia nuoren true aut une */wt+T) low cos = 3 Deat (%%+ to las maes & 78 EN ET circuit aut caet CSP 770)son McL0 81 EN (+7m) soo meaeg х ゴ عمو => Vo EN on N2 N3 예일 위일 N2 EN EN

by Lena's direction of Iz & Iz Can be determined if current En Entering the dot on the prom side then Secondary side current the dot must leave 또 direction of current Ni: No do dh 600 x-row Cos (wt) = ~12000 o mos | wt) waf four I came balance of TAFI IN'I = I2 Ng -> Ips Ne Iz qué bot * sufwx Ces (w+ +70) =-27W Cos (out) I, Now 11 Rin I

Nin - + 12000 to custot) I 27 w gas I wt) 12000 22 Rina 444.4502 Note :- frequency is not given that why y fined all in term of way woltenges and current