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(1 point) A random sample of 17 size AA batteries for toys yield a mean of 3.7 hours with standard deviation, 0.9 hours. (a)
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Answer #1

Solution :

(a)

t\alpha /2,df = 2.921

(b)

Margin of error = E = t\alpha/2,df * (s /\sqrtn)

= 2.921 * (0.9 / \sqrt 17)

Margin of error = E = 0.64

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