Question

A 4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm.

1)The image distance is:

Less than -4 cm

Between 0 and 4 cm

Greater than 4 cm

Between -4 and 0 cm

2) The magnitude of the image height will be:

Between 2 and 4 mm

Greater than 6 mm

Less than 2 mm

Between 4 and 6 mm

3) The image will be:

Real and upright

Virtual and upright

Virtual and inverted

Real and inverted

Answer 1

Soln Sign convention 4mm Icm C ft 6cm 12cm Focal length f = 2 12/2 - 6cm Mirror formula I V + te 44 Ve image distance distance u= th object fa focal leng ń - Ś 6 + -> -19 ㅗ 6 V- 3.6 cm Image distance image e distance is: Between and 4 cm (2 The (~) magi nitude of image height - magnification = h' h where h' h- height of object < 2 u height of image CS Scanned with CamScanner

hi h >13 3.6cm hi 4x10 cm ما cm h'= 0.16cm h = 1.6 mm height of image. tude of image 2 The nu mag image height height will be mm (w) Less than 2 © The image will be right ht (4) Virtua L and Scanned with CS CamScanner up