Question

A 4 mm high object is placed 5 cm in front of a concave mirror with a radius of curvature 20 cm.

1)The image distance is:

Between -15 cm and zero

Less than -15 cm

Greater than 15 cm

Between 0 and 15 cm

2) The magnitude of the image height will be:

Less than 3 mm

Between 3 and 6 mm

Greater than 9 mm

Between 6 and 9 mm

3) The image will be:

Virtual and inverted

Real and upright

Virtual and upright

Real and inverted

A 4 mm high object is placed 9 cm in front of a convex mirror with radius of curvature 12 cm.

1)The image distance is:

Less than -4 cm

Between 0 and 4 cm

Greater than 4 cm

Between -4 and 0 cm

2) The magnitude of the image height will be:

Between 2 and 4 mm

Greater than 6 mm

Less than 2 mm

Between 4 and 6 mm

3) The image will be:

Real and upright

Virtual and upright

Virtual and inverted

Real and inverted

Answer 1

R=2f f = R/2 20 =-10cm (focal point is on left side of the mirror). u=-5cm ( real i object). image distance & v. /f = Yu+Yu Yv=Yf-Yu v=10cm ) Real and upright V (between o and 15cm). ma - 10 m= -hi ho 4mm 김 - 4 = 2. -hi = 2 -hi-8mm. hiz-8mm. ( hoe between 6 and 9mm).