Question

Show your works and units for full credits 1. (a) A concave mirror has a radius of curvature of magnitude 40. cm. The object is 80. cm in front of the mirror. Find the image distance and the magnification. Is the image real or virtual? Is the image upright or inverted? M 1. (b) A concave mirror has a radius of curvature of magnitude 40. cm. The object is 25 cm in front of the mirror. Find the image distance and the magnification. Is the image real or virtual? Is the image upright or inverted? M

Answer 1

mirror * Salution (119));- u=-poem 1 с 70 object R = 40cm Cine "radius of Currature 1 Image f = b 40 -20cm 2 vie. F=-20cm From the mirror equation - 9 1 = Ltd f u where, f = focal length of the mirror U = chistance of the object from mirror. After putting the given values of dll parameters, 10 = dostemce of the we get image from mirror. LE+ - It -20 6-80) IE i +I 20 80 -4+1 11 el -3 80 80 3 V= -26.67cm. Ang Hence, the image distance will be 26.67cm left side from the mirror.

The linear magnification of the image 18 given by V m = и. then m =-(-26.67) (-80) m = -0.33 Ang The image will be real and inverted.

* Solution 10b) object Image. V U= -25cm I R= 40cm. ire. Va? f = &- to = 20 m=? f=-20cm From the mirror equation - ㅗ Itt f u After putting all the given values, we get- sdti -20 V -25 사 = -1 + 1 20 12 25 -5*4 100 -L 100 vo-100cm Ang Hence, the image distence will be 100 cm left side of the mirror.

The magnification of the image is given by m = u then, m = -100 -25 m-4 Ang Image will be real and inverted.