Question

Given a = 2.9 m and b = 1.8 m determin the angle CAD using either the dot product or Law of Cosines. P а B 0.6 m 2.25 m b 0.7
For the bracket shown with the forces P=950 N and Q = 550 N and distances a = 2.4 m and b= 1.5 m determin the moment about po
Moment about point D, Mo = k Nm Moment about rod CD, MCD Nm Click to select) was viewed from C towards D.
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Answer #1

a = 2.9m b=1,8 m C(1,2,0,0.75), A (0,2-9,0), 2(1.8, 9, - 2-25) AC Aă = 1.87 -2.93 +0.75R An= 1.8? - 2.97 - 2.25 k 0.75x2.25 AC (1.5, 0, +0.75) co = (-2.25-0.75) có =-3 Moment about nad CD ño.co 1425 x (-3), . McD = 3 * Mco = -1425 no as viewed 02 McD

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