Question

Using the angle method in the system in the figure, find the rotation of point B, the moment at the B end of the CB rod, the location and the value of the maximum moment in the CB rod.

Q(KN/m) 36,91 P(KN) 37.52 L1(m) 1,20   L2 (m) 2,33

a)Point B rotation fB (radians)

b)B end moment of CB rod MBC(kNm)

c)CB rod max moment location x (m)

d)CB rod maximum moment value Mmax(kNm)

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Answer #1

22 2.33m 4 = 1- 2m 2m Fixed and proment MAB = T9by = 0 MBC = + 212 + 38. 9. x 12,2 Faub = = 2 2 2 = 24.43 KN-M 12 = 74.43 KNMpoember BC tage = F BC + 288 ) ( 208 + OC - 3/2 - +4,43 +4 65 (208) MBC 244.43 + 6.67EFOB - ③ McB = MCB + 2560 120 + Gg - 31/raamber BD Мер - Таро — +15 .04 1км-и equilibrium equa neno consides gount coelibrium of Gorent B л 3. С. вс Час 12 Mon 116 1equili borim oqualiber aidoo jota el brilya oy folye 13 MC MA tho - 19 BA #19 BC =0 78.04 - 1 550 g + 6 143 + 6.6 65 0 [Er O

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Answer #1

22 2.33m 4 = 1- 2m 2m Fixed and proment MAB = T9by = 0 MBC = + 212 + 38. 9. x 12,2 Faub = = 2 2 2 = 24.43 KN-M 12 = 74.43 KNMpoember BC tage = F BC + 288 ) ( 208 + OC - 3/2 - +4,43 +4 65 (208) MBC 244.43 + 6.67EFOB - ③ McB = MCB + 2560 120 + Gg - 31/raamber BD Мер - Таро — +15 .04 1км-и equilibrium equa neno consides gount coelibrium of Gorent B л 3. С. вс Час 12 Mon 116 1equili borim oqualiber aidoo jota el brilya oy folye 13 MC MA tho - 19 BA #19 BC =0 78.04 - 1 550 g + 6 143 + 6.6 65 0 [Er O

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