Question

7. An object is placed at a distance of 80 cm left of a converging lens with a focal length of 30 cm. . Calculate the image distance. Is the image virtual or real? If the object is 8 cm tall, what is the size of the image? A diverging lens with the same focal length is placed 10 cm right of the first lens. Determine final image position and magnification. 8. A light ray strikes a flat piece of glass at an angle of incidence 30. The index of refraction of the glass is 1.5. The thickness of the glass is 2 cm. Trace the light ray until it emerges from the glass. 30° Air Glass 9. A light ray strikes a flat piece of glass at an angle of incidence 60. The index of refraction of the glass is 1.5. The thickness of the glass is 2 cm. Trace the light ray until it emerges from the glass. 60° Air Glass

Answer 1

7. ance object dief focal lengk 4 = -80 em. 230 em. Lens formula, using 1 / 2 - 4 u 30 80 tet 80-30 80x30 eu. 80x30 50 distance, 7 & 2 48 cm., image Grisen, object height h = 8em, Real. h, ha h) и 48 x 8 80 елм, 4.8em. size. image So, the object distance 1= (48 - 10) em » u = 38 24, f = -30 en 38 cm, 38x30 38-30 inagredistawe. - 142.5 en,

Катам f Cali sm) - M 192. Le 28 э ) м 2 3.1k Air Trace the light say umkil it gцаа 4 см, the glass. Glass.