Question

(a) What is the probability that in a randomly sampled individual, gene 1 is recessive? (b) What is the probability that in a randomly sampled individual, gene 2 is recessive? (c) Given that genel is recessive, what is the probability that gene 2 is recessive? (d) Two genes are said to be in linkage equilibrium if the event that gene 1 is recessive is independent of the event that gene 2 is recessive. Are these genes in linkage equilibrium? Part 1 of 4 The probability that gene 1 is recessive in a randomly sampled individual is 0.28 Part 2 of 4 The probability that gene 2 is recessive in a randomly sampled individual is 0.29 Part 3 of 4 The probability that gene 2 is recessive given that gene 1 is recessive is 0.3214 Part: 3/4 Part 4 of 4 5 The event that gene 1 is recessive (Choose one) independent of the event that gene 2 is recessive are not The genes (Choose one) in linkage equilibrium. are Slip Part Check Answer Save For Later Submit Assignin 2020 McGraw-Hill Education All Rights Reserved. Terms of Use

Answer 1

Part 3/4.

Answer is

The event that gene 1 is recessive is not independent of the event that gene 2 is recessive.

The genes are not in linkage equilibrium.

Detailed solution is given in the image below

Let B be A and two events such that A: Gene 1 is recessive in a randomly sampled individual. B: Gene 2 is recessive in a randomly sample individual (I am assuming that the answers in part 2, 2 and 3 are correct) P(A) = 0.28 (from part 1) PCB) 0129 (from part 2) P(BIA) = 0.3214 (from part 3): Events A and B are said to be independent if P(ADB) = PCA). P(8) Now, PCBA) = P (ADB) PA) P(ARB) P(BIA): P(A) = 0.3214 x 0.28 P(ANB)= 0.089992 : 1 and P(A). P(B) = 0.28 %0.29 0.0822 from ① & ② P(ADB) + P(A) P(B) Hence A and B are not independent events. ,: The genes are not in linkage equilibrium

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