Question

Google Calendar MUNCC A converging lens has a focal length of 62.0 cm. Locate the images for the following object distances, they exist. Find the magnification (Enter in the cand field in mages) G- M cm Select all that apply to part (a). real virtual upright Inverted no image (6) 20.7 cm Q om Select all that apply to part () real virtual O upright inverted no image (c) 279 cm cm Select all that apply to part (c). Oreal

Answer 1

(a f = 62.0 cm U =-62.0 cm By long formula Convex levy (converging leng) ture pe=q (Image distance, T at t u A S If the ha T l a ㅗ 62 19500 11 p=b 62 u ♡ -62 2005) W M= . u Real & Inverted, Image 14 magnification (m= re e प

(b) at = 62.0 cm Convex lens (Converging lens) u=-20.7cm | U By lens formula #*- & -t the [flere v=q Image ܛܘ distance - - 20.7 = 0.016-0.0483 q 62 9 - = q =) 0.0323 =) 19 =-30.95 cm Magnification May -30.95 -> M=1.495 - Image is virtual & Erect. (c) f = 62.0 cm f -->-270 + rol- u 4--279cm = 0.016-0.0035 = 0.0125 Image i Real & q= 80 cm Inverted -> Mit MA W SO -279 => M=-0.286