Question

Exercise 4: Plot salary as a function of yrs.since.phd Use the scatter() function to make a scatterplot with yrs.since.phd on the x axis and salary on the y-axts. Make sure you use the salaries_nonull dataframe you made in the previous step, Add "Salary vs. Yrs since PhD" as a title for the plot, and label the x-axis "Years since " and the y-axis "Annual Salary". You'll need the title xLabel and ylabel() methods. (TIP: try using tab autocomplete to explore what methods you have with pit to try this type pit then hit tab) In (13): # import the motplottib pyplot Library as plt import matplotlib.pyplot as plt Xpylab inline # Your code here # other code below here plt.title("Salary by Years since Phd") plt.xlabel("Years since Pho") plt:ylabel("Salary") Populating the interactive namespace fron numpy and matplotlib Out(13): Text(0,0.5, 'Salary") Salary by Years since Pha 225000 200000 175.000 150000

Answer 1

##in question the dataset is not provided, so creating some

##random data

##In case of any issues please comment, i will definitely help you.

##please rate +ve :)

import numpy as np

import pandas as pd

yrs_since_phd=np.random.randint(1,50,(25))

sal=np.random.randint(1,20,(25))*1000

salaries_nonull=pd.DataFrame({'yrs.since.phd':yrs_since_phd,'salary':sal})

#print(salaries_nonull)

##paste the code from here, no need of code above for your question

import matplotlib.pyplot as plt

#%pylab inline

#your code

plt.scatter(salaries_nonull['yrs.since.phd'],salaries_nonull['salary'])

plt.title("Salary vs. Yrs since Phd")

plt.xlabel('Yrs since Phd')

plt.ylabel('Salary')

##paste the code from here, no need of code above for your question import matplotlib.pyplot as plt #%pylab inline #your code plt.scatter(salaries_nonull['yrs.since.phd' ], salaries_nonull['salary']) plt.title("Salary vs. Yrs since Phd") plt.xlabel('Yrs since Phd') plt.ylabel('Salary') Text(0, 0.5, 'Salary') Salary vs. Yrs since Phd 17500 15000 12500 Salary 10000 7500 5000 2500 0 10 20 30 40 50