PYTHON --create a function that accepts a list of numbers and an int that returns...
PYTHON
--create a function that accepts a list of numbers and an int
that returns index of 2nd occurrence of the int in list, otherwise
returns None if # does not repeat more 2 or more times
EX: [10,24,3,45,10,49,4,5], 10) returns 4
--create a function that accepts a string that returns true if
every letter of the alphabet can be found at least one time in the
string, (has to be the lowercase alphabet), and false
otherwise.
for BOTH you can ONLY use these functions --- append, len, str, float, range, strip, split, int
Homework Answers
1.
Source Code:
def firstRepeat(lst,num):
count=0
for i in range(0,len(lst)):
if(lst[i]==num):
count=count+1
if(lst[i]==num and count==2):
return i
print(firstRepeat([10,24,3,45,10,49,4,5],10))
![main.py 1. def firstRepeat(lst, num): 2 count=0 3 for i in range(0, len(lst)): 4- if(lst[i]==num): 5 count=count+1 6 if(lst[i](http://img.homeworklib.com/questions/d51ada30-0459-11eb-adf1-1760ea8cde0f.png?x-oss-process=image/resize,w_560)
2.
Source Code:
def isAll(string):
isChar=False
alpha=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
for i in range(0,26):
isChar=False
for j in
range(0,len(string)):
if(alpha[i]==string[j]):
isChar=True
if(isChar==False):
return
False
return True
print(isAll("abcdefghijklmnopqrstuvwxy")) # returns false
because there is no 'z'
print(isAll("abcdefghijklmnopqrstuvwxyz")) # returns true
![,x,y,z] main.py 1def isall(string): 2 isChar=False 3 alpha=[a,b,c,d, e 4 for i in range(0,26): 5 ischar=Fals](http://img.homeworklib.com/questions/d634c2e0-0459-11eb-aef4-85cc2740595a.png?x-oss-process=image/resize,w_560)
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