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3. To make a buffer solution, you can start with a solution of a known number of moles of the base form (A) and add a strong

graduates example using an acid that we would NOT use in lab (at lea! considerations) to make a buffer. The first thing we ne

20 Buffers lab background reading used V We find that the pK, = -log(3.5 x 10“) which is 3.45593 as calculated, and 3.46 for

Which gives 10-0.47593 and therefore 0.3342489102 which would round to “1:3” for a small integer ratio. That means that if we

We can perform a check here at this point. We have a solution that contains more of the acid than the base, so we should expe


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