Question

Questions (34-35) Determine the allowable bending stress (Fb) and allowable Compression parallel to the grain (Fe) for a Douglas Pir-Larch 2 x 10 No. 2, used in repetitive framing with snow loading Question 34 Not yet answered Points out of 3.00 P Flag cuestion Pb- Select one O a. 1782 1b/in? O b. 1746 lb/in O c. 1309 lb/in O d. 1552 lb/in

Answer 1

Solution:

Question 34: Correct ans is B

Question 35: Correct ans is A

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with FC=? * Sol Given deti - Douglas Fior- Larch 2x10 NOI & Better repetitive framing Snow looding" Fo=? According to Natiarul Design Spesification (ND8) for wood Construction : From Table 4A - Visually graded dirieusion lumber -all Spécies except Soultern Prince For Douglas Fist- Laruh No.1 & Better, F = 1200 psi Tensien parallel cu grain (Ft) = 800 compression parallel ito grain (Fc) = 1550 pri

T1S withi Snew loads CD = 0.9 for dead cload anly 1.0 for Occupancy loads ✓ (given) Additional Adjustment faites are: CM = Correction feciter fer encessive Moisture. wen (FoCCP) $ 1150 psi, (M=ho (4 5. Correction fecetód for excessive high lengo to for. Fo, Fw, Fc & Fed CF = Size factor = 1.10. for width 10", bereadth 26 3 (= Amplification failor for repetitive use =1-15 for Dimension Lumber, a' to u" thick

Now: Allowable Bending Stren FI) - Fb (CD) (cm) (4)(Cr)() where Fb = 120opsi CD=115 (M = 1.0 A 10 CF = 1.10 Cr=1.15 Fb = 1200-(1.15) (10) (10) (1.1) (1.15) =1745.7 psi ~ 1746 Abliny 1746 psi

to : Allowable Compression parallel grain : Fi-Fc (D) (cmX(H) (CF) where Fc = 1550 pri D=115 (n = 10 (t = 10 CE=1.1 Fi: 1550 x 1.15X10X1.0 = 1782.5 pril 1782 Ablin?