Question

4. Draw the shear and moment diagrams for the compound beam. ((Lec/Tute a half) SkN/m

Answer 1

ANSWER :
22 0 5 kN/m. im * free body diagram for given figure is as follows. 5 kalm Skalon tom vo. consider portion AB EMA =0 Lv8x2= 5* 2 VB = 5KN Efy=0 VA = (-5x2)-5 VA = 5KN Consider portion BCD EMO=0 (542) + ( 5494c (vext) Vc = 20kn Sty=0 VCAVO = 5+(582) ND = -5KN)

shear calculations g sf at D = -(%) = -(-5)-5KN. State (Right of c) = -(-5)+5= 10 ka stat c. (leftofe) -(-5)+5-20 =-10KN. SE at BC Right of 8) =-(-5)+5-2015 =-5kn If at B (left of 6) =-5 kn Sfat A. ( Right of A) (Right of A) = -5+(582) 45KN Bendeng moment calculations BM at A=0 BM at B=0 •BM at D.=0 BM at C = -(5x1) - (5x 12 ) =-7.5KNM. BM at F 5x22 8 = 20 8. 20 = 2.5 kalim.

Skalmi 3 B NA VB 5 kallm. him Im 10 5 + t 5 (-) с 5 SFD. 10 215 kNam 14) e B. (-) BMD 7.5kN-m M