Question

For the truss shown a force H = 150 N is applied downward as shown. Given the dimensions in meters of a = 0.3, b = 0.25 , c = 0.18, d = 0.15, e = 0.15. Determine the force in members DG, EG, and FG. a b ws d x G C e E H

Answer 1

RO 1 solution: - From the problem we can take the given data G b d F с Z E ol # a=0.3, b=0.25, C=0:18, d= 0.15, e = 0015, H=150N H = - 150 » 7a Go from G. to D 2 TCD [0015 0.25k 10.25 24 0.15 0.18 0.15 0.25k » TOE = TGF 0.28² + 0015² +0.252 for equilibrium

1.286 X -direction : In *0.18 - 0.15Ť -0.959 TGE TGE 0.182 +0015²+0.252 < 0.22 TGE 0.22 THE it SO 001174 Voolity 0.22TGE 0.22TGE Ooll74 0.1174 ITGE= TGE Inz-direction: -ool TGD 0.-22 (TGF+TGE] = 0.085 0..127 T66/=(-22 CTGE E OLTAD. 2 x 0.22 TGF 0085 Vo.117 1:286 TGF X » - OTTGD Jooors TAD = 0.085 TGE 0.1 TGD = -3.749 TGF

In y direction: S 150+ 0.15 TGD 0.15 (TGF+TGE)zo 10:085 Voilla - 150 t 0.15 0015 X-3.749 TGE X 2G vo 10:085 √0.117 → -1.50 = +1.928 TGF +0.877 CE 150 -2.905 TGE olTGE -53.475 -53.475 TGF = compression > →TGE = -53.475 compression tension TGO 200.477