Question

Steam at 100° C is added to ice at 0° C. Find the amount of ice melted and the final temperature when the mass of steam is 3.00 g and the mass of ice is 50.0 g. 25.0 g, 38.8° C 50.0 g, 38.8° C 25.9 g,0° C 50.0 g, 43.8° C 24.1 g, 0° C

Answer 1

Solution of lf=Latent heat s= specific heat Lv= latent heat of vaporization = 2260J/g. fusion 34J/g water = of wat 4.25/g.c = heat given by steam when condense Hi= m steam Lu= 3x2260= 6780J - heat required to melt complete ice Cice to water at oc, H2 = micelf=50x334= 16,7005 => heat released by water( steam towater) to becomes af o'c = 3x4.2x100= 1260 J H3 M. SOT Stree H2) (41th 2 ) = whole i will not melt and Temperature will be 0°C → Heat given by steam= heat taken to the ice feo melting - Hi+43 = mif → 6780 +1260 = =mx334 24.07 m = melted ice (24.1g ing and 0°C =) Last option correct