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B. ENTHALPY OF NEUTRALIZATION NaOH temp. 29 HCl temp.: 22.0 Average temp. T: 22.06 Time Temp...
c. ENTHALPY OF SOLUTION Salt Sample: I Initial water temperature T:_21.3 Time Temp 10.30193 Calorimeter mass:...
c. ENTHALPY OF SOLUTION Salt Sample: I Initial water temperature T:_21.3 Time Temp 10.30193 Calorimeter mass: 3.816 193 Calorimeter + water mass: 102.483 11:30 193 Calorimeter + water + salt mass: 10.903 2.00 194 2.30 19.5 301%5 12.3 230 126 400 112.6 9.30 1127 Si og 198 119.8 (19.7 196 19.5 19.4 19.3 10:30 8 -2:00 2:30 13:00 -3:30 .4:00 4:30 5.00 Calculations: Calculated enthalpy of solution: Jig Salt is: Moles of salt: Calculated molar enthalpy of solution: J/mol ....
Table 4.2: Enthalpy of Neutralization for an Acid-Base Reaction Trial 1 Concentration of NaOH 1. i...
Table 4.2: Enthalpy of Neutralization for an Acid-Base Reaction Trial 1 Concentration of NaOH 1. i mol/L Initial temperature of NaOH 22.1°C Volume of NaOH Concentration of HCI 45, I mL 1.2 mol/L 22.3°C Initial temperature of HCI Trial 2 lol mol/L 21.9°C 63 mL 45. Iml 1,2 mol/L 22.5°C 45.2 mL 27.5° 22.2°C 5.3°C 90.3 mL 4.18 Jg! °C! Volume of HCI 45.3 ml Final temperature of mixture Average initial temperature (HCl and NaOH) Ti Temperature change, (47) 28.6°C...
calculate the experimental enthalpy per mole in this table. need immediately with clear steps. DATA: Table...
calculate the experimental enthalpy per mole in this
table.
need immediately with clear steps.
DATA: Table 1 Neutralization reaction 4.0957g Mass of calorimeter 54.503g 21°C Mass of calorimeter and HCI Temperature of HCI Final temperature of mixture 30°C 9°C Change in temperature 104.40g Mass of mixture and calorimeter 50.418 Mass of HCI 1.10M Molarity of HCI Volume of HCl (density= 1.02g/) 49.41ml 1.382 mol Moles of HCl Mass of NaOH 49.90g 1.00 M Molarity of NaOH 48.00 ml Volume of...
V. Heat of reaction for NaOH (s) + HCI (aq) → Naci (aq) + H20 ()-dH(net) Direct determination Mas...
need help with calculations
V. Heat of reaction for NaOH (s) + HCI (aq) → Naci (aq) + H20 ()-dH(net) Direct determination Mass NaOH Moles NaOH = moles Mass of HCI solution Final temp. of solution Initial temp. of solution AT solution 30 23 C 4 C AH(net)(Direct) per mole NaOH Calculation Indirect determination Heat of dissolution of NaOH (s) [AH(diss)] Mass NaOH Moles NaOH moles Mass of water Final temp. of solution Initial temp. of solution AT solution AH(diss)-...
to determine the enthalpy of neutralization, you will construction a time verus temperature graph. why is...
to determine the enthalpy of neutralization, you will
construction a time verus temperature graph. why is this graph
necessary?
WA UWEP 1. To determine the enthalpy of neutralization, you will construction a time versus temperature graph. Why is this graph necessary? 2. A student added 2.500 g MgSO4(MM 120.4) to a 60.000 g water sample. The initial temperature of the water was 20.50 *C. After adding the salt, the temperature rose to 27.00°c. a) What is the value of AT?...
i need help on the second page: "calculate how many mols of HCL you used based...
i need help on the second page:
"calculate how many mols of HCL you used based on the volume
and molarity of the HCL"
and
"enthalpy of reaction" parts
Part B Heat of Reaction for HCl(aq) + NaOH (aq) NaCl (aq) + so H20 (1) Volume of 1.0 M HCl (ml) so 100 23.3 Volume of 1.0 M NaOH (ml) Mass of Solution (8) use 1.00 g/ml Ti solution (temp of HCl just before reaction) T solution (highest temp obtained)...
Please use part C data to solve question 1. The theoretical value is -57.3kJ/mol to compare...
Please use part C data to solve question 1. The
theoretical value is -57.3kJ/mol to compare answer to. Calorimeter
constant is 22.1J/gC
PART C Data Analysis: 1. Calculate the heat of neutralization (AH.eu) for each trial 2. Calculate the average, standard deviation, and relative percent standard deviation for your three trials 3. Calculate the percent error based on your average and the theoretical value given in your data set. Data Trial 3 45.120 g 105.687 g Trial 1 Trial 2...
Thermodynamics: heat of reaction, temp change, ans enthalpy of reaction. Please help me! I am so...
Thermodynamics: heat of reaction, temp change, ans enthalpy of
reaction. Please help me! I am so lost! thank you!
Lab Partners: Name For our calculations, we will assume that the heat capacity of each solution is 4.18J/g.c, because aqueous solutions are in fact mostly water. Data and Results Sheet Initial Initial Expt. # moles moles он Theo. Yield of H20 formed Limiting Reactant T (°C) Mass of solution (B) ΔΗ (kl/mol) T (C) AT (°C) q absorbed by solution 0...
im trying to solve for the remaining but im confused please help this is experiment 25...
im
trying to solve for the remaining but im confused please help this
is experiment 25 Calorimetry
HNO B. Enthalpy (Heat) of Neutralization for an Acid-Base Reaction H Poting flendar HCI + NaOH uuemliojo Trial 1 Trial 2 1. Volume of acid (mL) 50 - 60 Site 2. Temperature of acid (C) ao 20" 3. Volume of NaOH (ml) 20 4. Temperature of NaOH (C) Trial 1 5. Exact molar concentration of NaOH (mOVL) 6. Maximum temperature from graph (°C)...
c. ENTHALPY OF SOLUTION Salt Sample: I Initial water temperature T:_21.3 Time Temp 10.30193 Calorimeter mass: 3.816 193 Calorimeter + water mass: 102.483 11:30 193 Calorimeter + water + salt mass: 10.903 2.00 194 2.30 19.5 301%5 12.3 230 126 400 112.6 9.30 1127 Si og 198 119.8 (19.7 196 19.5 19.4 19.3 10:30 8 -2:00 2:30 13:00 -3:30 .4:00 4:30 5.00 Calculations: Calculated enthalpy of solution: Jig Salt is: Moles of salt: Calculated molar enthalpy of solution: J/mol ....
Table 4.2: Enthalpy of Neutralization for an Acid-Base Reaction Trial 1 Concentration of NaOH 1. i mol/L Initial temperature of NaOH 22.1°C Volume of NaOH Concentration of HCI 45, I mL 1.2 mol/L 22.3°C Initial temperature of HCI Trial 2 lol mol/L 21.9°C 63 mL 45. Iml 1,2 mol/L 22.5°C 45.2 mL 27.5° 22.2°C 5.3°C 90.3 mL 4.18 Jg! °C! Volume of HCI 45.3 ml Final temperature of mixture Average initial temperature (HCl and NaOH) Ti Temperature change, (47) 28.6°C...
calculate the experimental enthalpy per mole in this
table.
need immediately with clear steps.
DATA: Table 1 Neutralization reaction 4.0957g Mass of calorimeter 54.503g 21°C Mass of calorimeter and HCI Temperature of HCI Final temperature of mixture 30°C 9°C Change in temperature 104.40g Mass of mixture and calorimeter 50.418 Mass of HCI 1.10M Molarity of HCI Volume of HCl (density= 1.02g/) 49.41ml 1.382 mol Moles of HCl Mass of NaOH 49.90g 1.00 M Molarity of NaOH 48.00 ml Volume of...
need help with calculations
V. Heat of reaction for NaOH (s) + HCI (aq) → Naci (aq) + H20 ()-dH(net) Direct determination Mass NaOH Moles NaOH = moles Mass of HCI solution Final temp. of solution Initial temp. of solution AT solution 30 23 C 4 C AH(net)(Direct) per mole NaOH Calculation Indirect determination Heat of dissolution of NaOH (s) [AH(diss)] Mass NaOH Moles NaOH moles Mass of water Final temp. of solution Initial temp. of solution AT solution AH(diss)-...
to determine the enthalpy of neutralization, you will
construction a time verus temperature graph. why is this graph
necessary?
WA UWEP 1. To determine the enthalpy of neutralization, you will construction a time versus temperature graph. Why is this graph necessary? 2. A student added 2.500 g MgSO4(MM 120.4) to a 60.000 g water sample. The initial temperature of the water was 20.50 *C. After adding the salt, the temperature rose to 27.00°c. a) What is the value of AT?...
i need help on the second page:
"calculate how many mols of HCL you used based on the volume
and molarity of the HCL"
and
"enthalpy of reaction" parts
Part B Heat of Reaction for HCl(aq) + NaOH (aq) NaCl (aq) + so H20 (1) Volume of 1.0 M HCl (ml) so 100 23.3 Volume of 1.0 M NaOH (ml) Mass of Solution (8) use 1.00 g/ml Ti solution (temp of HCl just before reaction) T solution (highest temp obtained)...
Please use part C data to solve question 1. The
theoretical value is -57.3kJ/mol to compare answer to. Calorimeter
constant is 22.1J/gC
PART C Data Analysis: 1. Calculate the heat of neutralization (AH.eu) for each trial 2. Calculate the average, standard deviation, and relative percent standard deviation for your three trials 3. Calculate the percent error based on your average and the theoretical value given in your data set. Data Trial 3 45.120 g 105.687 g Trial 1 Trial 2...
Thermodynamics: heat of reaction, temp change, ans enthalpy of
reaction. Please help me! I am so lost! thank you!
Lab Partners: Name For our calculations, we will assume that the heat capacity of each solution is 4.18J/g.c, because aqueous solutions are in fact mostly water. Data and Results Sheet Initial Initial Expt. # moles moles он Theo. Yield of H20 formed Limiting Reactant T (°C) Mass of solution (B) ΔΗ (kl/mol) T (C) AT (°C) q absorbed by solution 0...
im
trying to solve for the remaining but im confused please help this
is experiment 25 Calorimetry
HNO B. Enthalpy (Heat) of Neutralization for an Acid-Base Reaction H Poting flendar HCI + NaOH uuemliojo Trial 1 Trial 2 1. Volume of acid (mL) 50 - 60 Site 2. Temperature of acid (C) ao 20" 3. Volume of NaOH (ml) 20 4. Temperature of NaOH (C) Trial 1 5. Exact molar concentration of NaOH (mOVL) 6. Maximum temperature from graph (°C)...
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