B) FIND THE CRITICAL VALUES
C) Is there sufficient evidence to conclude that there is a linear
correlation between the two variables?
X | Y |
112 140 115 140 130 110 100 120 |
64 75 59 73 71 56 54 68 |
X - Mx | Y - My | (X - Mx)2 | (Y - My)2 | (X - Mx)(Y - My) |
-8.875 Mx: 120.875 |
-1.000 My: 65.000 |
78.766 Sum: 1482.875 |
1.000 Sum: 448.000 |
8.875 Sum: 768.000 |
Key
X: X Values
Y: Y Values
Mx: Mean of X Values
My: Mean of Y Values
X - Mx & Y -
My: Deviation scores
(X - Mx)2 & (Y -
My)2: Deviation
Squared
(X - Mx)(Y -
My): Product of Deviation Scores
Result Details & Calculation
X Values
∑ = 967
Mean = 120.875
∑(X - Mx)2 = SSx = 1482.875
Y Values
∑ = 520
Mean = 65
∑(Y - My)2 = SSy = 448
X and Y Combined
N = 8
∑(X - Mx)(Y - My) = 768
R Calculation
r = ∑((X - My)(Y - Mx)) /
√((SSx)(SSy))
r = 768 / √((1482.875)(448)) = 0.9423
r= 0.942 means their is strong correlation between X and Y
b)
N=8
Significance Level: | 0.05 |
Degrees of Freedom(N-2): | 6 |
Critical value(two tailed) = +/- 0.707
Critical value (or tailed) = 0.621.
c)
r= 0.942 means their is strong correlation between X and Y
This is a strong positive correlation, which means that high X variable scores go with high Y variable scores (and vice versa).
Thank You...|||
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