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The 0.02 kg bullet is travelling at 400 m/s when it becomes embedded in the 2 kg stationary block. The coefficient of kinetic

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Conservation of Momentum 2.02(9:8) N (†) Imbustim BVB=(moting Ff=0.90 0.02(400) +0=(0.02+2) V v=3.9604 m/s Principal of impul

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