A 0.0260 kg bullet moving horizontally at 450 m/s embeds itself into an initially stationary 0.500...
A0.0240 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg block (a) What is their velocity (in m/s) just after the collision? m/s (b) The bulet-embedded biock slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction, Now what is its velocity (in m/s)? m/s (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far (in m) does this combination travel before stopping? m
can you please help with part C thanks! A 0.0230 kg bullet moving horizontally at 450 m/s embeds itself into an initially stationary 0.500 kg block. (a) What is their velocity (in m/s) just after the collision? 19.79 (b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity (in m/s)? 18.56 (c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far...
A bullet of mass 0.056 kg traveling horizontally at a speed of 100 m/s embeds itself in a block of mass 1.5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? v= m/s (b) Calculate the kinetic energy of the bullet plus the block before the collision: K; = (c) Calculate the kinetic energy of the bullet plus the block after the...
A 35.0 g bullet strikes a 5.5 kg stationary wooden block and embeds itself in the block. The block and bullet fly off together at 7.0 m/s. What was the original speed of the bullet?
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 4 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vf = m/s ) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = Ktrans,f = (c) Compare the two results and explain why there is a...
A bullet of mass 0.017 kg traveling horizontally at a high speed of 210 m/s embeds itself in a block of mass 5 kg that is sitting at rest on a nearly frictionless surface. (a) What is the speed of the block after the bullet embeds itself in the block? Vr = 42 x m/s (b) Calculate the total translational kinetic energy before and after the collision. Ktrans,i = 374.85 Ktrans,f= (c) Compare the two results and explain why there...
A 10.0-g bullet is fired into, and embeds itself in, a 1.95-kg block attached to a spring with a force constant of 20.0 N/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Note: You must use conservation of momentum in this problem because of the inelastic collision between the bullet and block.
A 10.0-g bullet is fired into, and embeds itself in, a 1.80-kg block attached to a spring with a force constant of 22.3 N/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Note: You must use conservation of momentum in this problem because of the inelastic collision between the bullet and block.
2) A 10.0-g bullet is fired into, and embeds itself in, a 1.80-kg block attached to a spring with a force constant of 22.4 N/m and whose mass is negligible. How far is the spring compressed if the bullet has a speed of 300 m/s just before it strikes the block and the block slides on a frictionless surface? Note: You must use conservation of momentum in this problem because of the inelastic collision between the bullet and block. ___...
A 10.0 gram bullet traveling at 275 m/s strikes and embeds itself in a 3.490 kg block of wood held on a frictionless table by a spring having k= 50.0 kg/sec^2. Calculate the speed of the block immediately after the collision and the compression of the spring in meters.