time of Q1:- Calculate the instantaneous and Long- deffection (time limit 5 years) of a no...
Long-time Q1:- Calculate the instantaneous and deflection (time limit of 5 years) of a no pt span Simply supported beam (n=8), fé-u ksi, fyz boksi (50%) 205 W2 = 1x18t WO = 2k/ft 12 = 12 * Po=104 2 #10 22-5 3oft post 6#) 3.5 t 16"
Qli- Calculate the instantaneous and long-time deflection (time limit of 5 years of a no ft span Simply supported beam (n=8), fc-uksi, fyz boksi (50%) W2 = 1 x 1 lt 12 = 12k 2.5 WD2K/ft Po=104 2 #10 3oft 22.5 posta 6#1 3.5" t 16 +
urgent
time - Calculate the instantaneous and Long- deflection (time limit of 5 years of a no ft span Simply supported beam (n=8). fc = Hksi, fy= boksi W2 = 1x18t Wo=2k1ft 12 = 12k 2.5 # Po=16* 2#10 3oft (22.5 Klopp 6#) 13.5 th
please answer the following
time Q1:- Calculate the instantaneous and Long- deflection (time limit of 5 years of a no ft span simply supported beams (n=8). fr=uksi, fy=boksi (50%) w =) кі 10= 12к Mp3 2 Kik Po=104 2.5 $ 2#jo Зор Jolt 22.5 Олония ## VoITAllMAXB MARTIN 3.5"
Qli- Calculate the instantaneous and long-time deflection (time limit of 5 years) of a no ft span simply supported beam (n=6), fiziksí, for boksi" (50%) us=1x1Bt 12= 12 * Wo= 2K1ft 2.5 I P0 2 #10 30pt kollen 22.5 6# 13.5
PLEASE SHOW WORK. WILL UPVOTE! Only need Shear &
Moment Diagrams
5) A 30 foot long simply-supported beam supports the unfactored loads shown in the figure. The uniformly distributed dead load, wo, includes the self-weight of the beam, and is constant along the full beam length. Two different uniformly distributed live loads, wuu and wiz are applied as indicated. Concentrated dead, PD, and live, Pt, loads are applied as shown in the figure. Draw factored shear force and factored bending...