In an ionic solution, 5.0×1015 positive ions with charge +2e pass to the right each second...
In an ionic solution, 5.0×1015 positive ions with charge +2e pass to the right each second while 6.0×1015 negative ions with charge −e pass to the left.
What is the magnitude of current in the solution? (mA)
What is the direction of current in the solution? (left or right?)
Homework Answers
n1 = no of positive ions = 5*1015
q1 = charge on positive ions = 2e
n2 = no of negative ions = 6*1015
q2 = charge on negative ions = - e
also e = 1.6*10-19 C
time, t = 1 sec
current , I = q / t
current will be in the direction of positive ions ie towards right.
so I = ( q1 + q2 ) / t
I = ( 5* 1015 *2*1.6*10-19 + 6*1015*( - 1.6*10-19)*( -1) ) ( q = ne)
[ multiply by (-1) because negative ions in opposite direction to that of positive ions)
I = 2.56 mA
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