Question

use python IDEL

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Problem 1 Lists. Read the following code and answer the next five questions about it. X = ? y=? z = ? zodiac = ["cow", "tiger", "rabbit", "dragon", "snake", "horse" "sheep", "monkey", "dog", "chicken", "pig", "rat"] first_group = zodiac[0:x] second_group = zodiac[x:y] third_group - zodiac[y:z] animals = [] for item in first_group: animals.append(item) for item in third_group: animals.append(item) for item in second group: animals.append(item) #first print statement print (animals) i = ? j = ? for animal in zodiac: if animal == animals[i]: item- animals.pop(i) animals.insert(j, item) +=1 #second print statement print(animals)

Answer 1

Solution 1:-

Correct answer - 4

The value of x is 4 as then zodiac[0:4] as it will slice upto index 3 of the list and first_group will contain items from cow to dragon.

Solution 2:-

Correct answer - 7

The value of y is 7 as then zodiac[4:7] as it will slice upto index 6 of the list and second_group will contain items from snake to sheep.

Solution 3:-

Correct answer - 13

The value of z is 13 as then zodiac[7:13] as it will slice upto index 12 of the list and third_group will contain items from monkey to rat.

Solution 4:-

Correct answer - 0

The value of i is 0 as there is matching done of the elements in animals list and the zodaic list so only first four elements will be matched and will be poped and then inserted.

Solution 5:-

Correct answer - 0

The value of j is 0 as there is matching done of the elements in animals list and the zodaic list so the elements poped are inserted in the manner as element inserted at the top of stack. So the desired output will be produced as stated in the problem statement.