Question

PLEASE ANSWER QUESTION 1 & 2. ALSO PLEASE SUBMIT CODE + PDF OF REPORT/ASSIGNMENT

Problem1 You are choreographing a circus show with various animals. For one act, you are given two kangaroos on a number line ready to jump in the positive direction (i.e, toward positive infinity). The first kangaroo starts at location z1 and moves at a rate of vl meters per jump. The second kangaroo starts at location z2 and moves at a rate of u2 meters per jump. You have to figure out a way to get both kangaroos at the same location at the same time as part of the show. If it is possible, return YES, otherwise return NO For example, kangaroo 1 starts at zl = 2 with a jump distance v1 = 1 and kangaroo 2 starts at x2 = 1 with a jump distance of v2-2. After one jump, they are both at z-3.(z1 vl 2+1 x22 1+2), so our answer is YES Input Format A single line of four space-separated integers denoting the respective values of 1, v1, 2, and v2. Constraints OSal z1). Because the second kangaroo moves at a faster rate (meaning v2 > vi) and is already ahead of the first kangaroo. the first kangaroo will never be able to catch up. Thus, we print NO Problem 2 Show that a set S is infinite if and only if there is a proper subset A of S such that there is a one-to-one correspondence (e.g., one-to- one and onto) between A and S.

Answer 1

IF YOU HAVE ANY DOUBTS COMMENT BELOW I WILL BE TTHERE TO HELP YOU..ALL THE BEST..

AS FOR GIVEN DATA.

close all
clear
clc

% Processing the input to create a vector
vec = input('Enter the input: ', 's');
vec = strsplit(strtrim(vec));
for i = 1:length(vec)
vec{i} = str2double(vec{i});
end
vec = cell2mat(vec);

% Basically, we need to figure out the value of k such that
% x1 + k*v1 = x2 + k*v2, where k need to be a positive integer (number of jumps)
% This gives, k*(v1 - v2) = (x2 - x1) => k = (x2 - x1)/(v1 - v2)
x1 = vec(1); v1 = vec(2); x2 = vec(3); v2 = vec(4);

if (x1 == x2 && v1 ~= v2) || (x1 ~= x2 && v1 == v2)
disp('NO')
else
if (x1 == x2 && v1 == v2)
disp('YES')
else
k = (x2 - x1)/(v1 - v2);
if floor(k) == k
disp('YES')
else
disp('NO')
end
end
end

Sample Output 1:

Enter the input: 2 1 2 1
YES

Sample Output 2:

Enter the input: 0 3 4 2
YES

Sample Output 3:

Enter the input: 1 1 2 1
NO

I HOPE YOU UNDERSTAND..

PLS RATE THUMBS UP..ITS HELPS ME ALOT..

THANK YOU...!!