Question

The cantilever, shown, has a steel core bonded to a wood casing. If a concentrated load 25 kN is applied at its end, determine the maximum bending stress in the cantilever. Ew = 12 GPa, Es = 200 GPa. 25 kn 3.00 m 200 mm 200 mm Steel 500 mm Wood 500 mm Cross-section of the cantilever

Answer 1

Saution Here, B-svomm. 9- 200m 17 Soumm=b stel 2oon. అంది By Banding equation M I Mibending moments a Benting stress. Soomm 660 = 8 Neutral axis free end, from Here I moment of gertia daM Ya distance from Maximum Benting stress occurry at place where Benting moment is maximum. In cantilever Beam, loades at the maximum bending moment occurs at fixed and IP=25ky So, Maximum Reading Moment, rinora 25x3 mas a Pro ལྟ་བ Lim = 75 kayam Monary - 75x108 4-mm Benting moment diagram This maximum bending moment will be resepted by bean section auf and will be equal to Resistance of Began CMOR) moment g Monox = MOR

MOR steel - as 93 652 82 6 MORwool awa? 612 MOR = MORwood + Morstel (MOR awal MOR - al AS we know ose mow - 16.67ow las (6. crow from hs. 500/2 Ble 2001 9/62 ovo = 1.768 ow putting this values in equating 0 MOR= 1.768 ow R3 6 aw a3 16.670w al + 652 62 25x3x10 = t. 768 d w x 2003 + 16.67 aw x 200 1.768 xaw x 5003 75x100 6 6.62 aw = 1.953 N/mm2 as = 10.cztowa 24.22 N/mm 2 [RW = 1.768 xow = 2.569 W/mm2

So, The Denting stress diagram will be aw, 22.5634/mm2 Za 43 limuna 200 14.924 0s= 24. 22810m2 4. So the maximum bending stress occurs in extreme fiber of Steep and it occures at fixed en 8 beam ( cantilever). Its value is 24. 22/ram And... Maximum Bending stress in Cantilwar, amax = ns = 24.2211 mm2 - Unit Conversion resul lky = 1024 - 103 mm M-om? Licy-m = 100 N.