Question

The cantilever, shown, has a steel core bonded to a wood casing. If a concentrated load 25 kN is applied at its end, determine the maximum bending stress in the cantilever. Ew = 12 GPa, Es = 200 GPa. 25 kN 3.00 m 200 mm 200 mm Steel 500 mm Wood 500 mm Cross-section of the cantilever

Answer 1

25 KN 3 I Ishlood Ew = 12 Gpa ES -200 Gpa 500 4200 Steel M = Mt Mg 25x3 = Met MS > Mat Mg = 75 knom ~ Radius of curvature of wood - Steel 수 등 ě w C). Ey Eys 9 200 45 yw = 500 = 250 y = 200 11 Our Os sinu5= Ys 200. Ys = 2001 va 12 x 250 200 x 200 Os=9.4280W 2 M IXE 놈 er ) - ) 200 2002x 200 3 200 & 45 2x200cosus - 2007 8 Is = 1:33x10 mm mmy

22-83x10 x 200 Is In = Itotal 500 u 1-337108 il 12 10 9 5.075X10 Iw= MW 5.015x109x12 Ms 1.33x108x x 200 Mwl = 2.289x MS => 3-289 Mg = 75 KN-m M = 2283 kNm → Muis knom 52.19 6 Ow= Mue xyu 52.19x10 x 250. In! 5.075x10 Ow= 2.571 mpa 6 Os= Ms xYs Is 1-33x108 Os = 24.275 mpa
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