Question

In the titration of 12.1 mL of a 0.183 weak base solution (Kb = 7.7 ×...

In the titration of 12.1 mL of a 0.183 weak base solution (Kb = 7.7 × 10-7) with 0.22 M HCl solution, what is the pH at the equivalence point? (Hint: first find the equivalence volume and total volume)

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
In the titration of 12.1 mL of a 0.183 weak base solution (Kb = 7.7 ×...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Consider the titration of 50.0 mL of 0.133 M NH3 (a weak base with Kb =...

    Consider the titration of 50.0 mL of 0.133 M NH3 (a weak base with Kb = 1.76 x 10-5 ) with 0.223 M HCl (a strong acid). Calculate the pH of the solution at each of the following points: 1. What is the pH of the solution before the titration is begun? 2. What is the pH of the solution after the addition of 15 mL of HCl? 3. What is the pH of the solution at the equivalence point?...

  • In the titration of a 25 mL of 0.245 M weak base (Kb = 1.76*10^-5) being...

    In the titration of a 25 mL of 0.245 M weak base (Kb = 1.76*10^-5) being titrated by 0.365 M HCl determine the following: a. The PH at the initial point b. The PH after 12.3 mL of HCl has been added c. The PH at the equivalence point d. The PH after 18.4 mL of HCl has been added

  • You have 15.00 mL of a 0.100 M aqueous solution of the weak base C5H5N (Kb...

    You have 15.00 mL of a 0.100 M aqueous solution of the weak base C5H5N (Kb = 1.50 x 10-9). This solution will be titrated with 0.100 M HCl. (a) How many mL of acid must be added to reach the equivalence point? (b) What is the pH of the solution before any acid is added? (c) What is the pH of the solution after 10.00 mL of acid has been added? (d) What is the pH of the solution...

  • You have 25.00 mL of a 0.100 M aqueous solution of the weak base CH3NH2 (Kb...

    You have 25.00 mL of a 0.100 M aqueous solution of the weak base CH3NH2 (Kb = 5.00 x 10-4). This solution will be titrated with 0.100 M HCl. (a) How many mL of acid must be added to reach the equivalence point? (b) What is the pH of the solution before any acid is added? (c) What is the pH of the solution after 5.00 mL of acid has been added? (d) What is the pH of the solution...

  • Sera titrates a 10.00 mL sample of a 0.0750 M weak base (A4-) with 0.2500 M...

    Sera titrates a 10.00 mL sample of a 0.0750 M weak base (A4-) with 0.2500 M HCl, a strong monoprotic acid. The Kb values for this base are Kb1 = 2.00 x 10-3, Kb2 = 3.00 x 10-6, Kb3 = 4.00 x 10-9, and Kb4 = 5.00 x 10-11. Calculate the volume of HCL, in mL, needed to reach the first equivalence point of this titration. Calculate the pH of the titration solution after 4.50 mL of HCl has been...

  • You have 40.00 mL of a 0.300 M aqueous solution of the weak base C6H5NH2 (Kb = 4.00 x 10-10). This solution will be titr...

    You have 40.00 mL of a 0.300 M aqueous solution of the weak base C6H5NH2 (Kb = 4.00 x 10-10). This solution will be titrated with 0.300 M HCl. (a) How many mL of acid must be added to reach the equivalence point? (b) What is the pH of the solution before any acid is added? (c) What is the pH of the solution after 10.00 mL of acid has been added? (d) What is the pH of the solution...

  • 3. Weak Base versus Strong Acid Derive a titration curve for the titration of 50.0 mL of 0.10 M NH3 (Kb=1.8 x 10-5) wit...

    3. Weak Base versus Strong Acid Derive a titration curve for the titration of 50.0 mL of 0.10 M NH3 (Kb=1.8 x 10-5) with 0.25 M HCl. Calculate the pH for the following volumes of HCl (0 mL, 10 mL, 15 mL, 20 ml, 25 mL, 30 mL, 35 mL). Volume of HCI, in milliters 0 pH (a) 10 15 (d) 20 |(f) 25 30 35 (g) pH at the equivalence point Specify your choice of indicator

  • 1))))Weak Base Titration: At the Equivalence Point a))A 11.30 mL solution of 2.47 M pyridine (C5H5N,...

    1))))Weak Base Titration: At the Equivalence Point a))A 11.30 mL solution of 2.47 M pyridine (C5H5N, a weak base) is titrated to the equivalence point with 22.4 mL of HNO3. What is the pH at the equivalence point? Kb for pyridine is 1.7 X 10-9. b))))Click on all of the dominant species that you would expect to find in solution at the equivalence point. Do not include H3O+ and OH-ions unless they are coming from another source other than the...

  • NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180...

    NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180 MNH3 is titrate using HCl. The end point is reach after 35.0 mL HCl had been added. Calculate the pH of the resulting solution at the equivalence-point. Here is the titration equation:NH3(aq) + HCl(aq) →NH4Cl(aq)

  • 3. The pH of a 0.345 M weak base solution is 9.39. 50.0 mL of the...

    3. The pH of a 0.345 M weak base solution is 9.39. 50.0 mL of the weak base are titrated with 0.425 M HCI. a. Calculate the Kb of the weak base. b. Calculate the Ka of the weak base. c. d. Consult a Chemistry text and determine the identity of the weak base. Calculate the volume of HCl required to reach the equivalence point.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT