NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180...

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NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180...

NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180 MNH3 is titrate using HCl. The end point is reach after 35.0 mL HCl had been added. Calculate the pH of the resulting solution at the equivalence-point. Here is the titration equation:NH3(aq) + HCl(aq) →NH4Cl(aq)

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Add Answer to: NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180...

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NH3 is a weak base with a Kb value of 1.76x10–5. Suppose 25.0 mL of a0.180...