Question

Place an unknown mass at the 10 cm mark of the meter stick. Suspend from the other side a counter mass m2 = 300g and adjust i
m=? X = 10 cm = m, = 300 g X2 = 87.0 cm 02 = m_270 g (measured on scale/ accepted) m (calculated, experimental) % error
Data Table Mass of meter stick, Masterstick = 87g Balancing point center of mass) of meter stick, *, - 50.5 cm
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Answer #1

= The level arm: ri = Xo – X1 50.5 – 10 = 40.5 cm = 0.405 m r2 = x2 – Xo = 87.0 - 50.5 = 36.5 cm = 0.365 m Using: Et=0 migri

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