Question

Place m, = 100g at the 20-cm mark and m2 = 200g is at the 60-cm mark on the meter stick. Experimentally determine the positio
Case 2 m = 100 g x1 = 20 cm TE 200 g ra T си X2 = 60 cm X3 = 73.5 cm mg = 50 g ry = %.Diff.
Data Table Mass of meter stick, Masterstick = 87g Balancing point center of mass) of meter stick, *, - 50.5 cm
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Case 2 m 100 g x1 = 20 cm 30.5 cm 0.2989 Nm Tec 200 g 9.5 cm r2 т 0.1862 Nm CW X2 = 60 cm X3 = 73.5 cm m 50 g = 23 cm %.Diff.

Add a comment
Know the answer?
Add Answer to:
Place m, = 100g at the 20-cm mark and m2 = 200g is at the 60-cm...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Place m = 100g at the 20-cm mark and m2 = 200g is at the 60-cm...

    Place m = 100g at the 20-cm mark and m2 = 200g is at the 60-cm mark on the meter stick. Experimentally determine the position for mz = 50g so that the system is in equilibrium. Follow a procedure similar to steps 2 and 3. Compute the percent difference of the clockwise and counterclockwise torques. See Figure. X axis X X2 X₂ ma m2 m3 Case 2 x1 = 20 cm CC m = 100 g m2 = 200 g...

  • at With the meter stick on the support stand, suspend a gram mass m = 100g...

    at With the meter stick on the support stand, suspend a gram mass m = 100g the 15-cm mark on the meter stick. Then adjust the lever arm for a gram mass m2 = 200g on the other side of the axis. See Figure. X axis X X2 m m2 Record the mass and position x as read on the meter stick and then record the lever arms. Compute the torques and find a percent difference between the clockwise (Tow)...

  • Suspend a mass m, =100g at or near the zero end of the meter stick. Move...

    Suspend a mass m, =100g at or near the zero end of the meter stick. Move the meter stick in the support clamp until the meter stick is in equilibrium. Record this new equilibrium position as x," Using the total mass of the meter stick, calculate the clockwise and counterclockwise torques, and then calculate a percent difference. In this calculation, you will include the mass of the meter stick as if it were concentrated at its center of mass, x,...

  • Place an unknown mass at the 10 cm mark of the meter stick. Suspend from the...

    Place an unknown mass at the 10 cm mark of the meter stick. Suspend from the other side a counter mass m2 = 300g and adjust its position until the system is in static equilibrium. Using, Στ = 0 calculate the unknown mass m². Remove the unknown mass and determine its mass on the laboratory balance. See Figure. This is the accepted mass. Calculate % error. % Error lexperimentalacceptedy 100 accepted X axis X X2 m m, m=? X =...

  • the fulcrum is positioned at the 50cm mark on the meter stick. A 50g mass is...

    the fulcrum is positioned at the 50cm mark on the meter stick. A 50g mass is hung from 67 m mark on the stick. Also a 200g mass is suspended from the 89 cm mark. A. Calculate the total clockwise torque due to these masses B. assuming that the total counterclockwise torque is equal to the answer in (A) above, calculate the position on the meter stick where 315g mass must be suspended in order to balance the stick.

  • can ignore friction when they ispherical bowl of II. A) In this part of the laboratory...

    can ignore friction when they ispherical bowl of II. A) In this part of the laboratory you will explore the basic concept of rotational equilibrium, i.e. the balancing of torques about a fulcrum or pivot point. You will be given values for 3 masses along with given positions (X) on a meter stick for which two of these masses will be hung. Your task is to determine the position that the third mass must be hung in order to balance...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT