Question

Table 1: Resistance (2) Voltage (V) At battery Current (A) In circuit Voltage measured across Resistor 1/R _(0-1) 10 0.88 0.088 40 0.18 0.0045 50 0.17 0.0034 80 0.10 0.00125 100 0.089 0.00089

Pleaseee do as much as you can but the most important one is to finish the table calculation and question 3

Answer 1

To complete the table using OHM'S law V = I * R

Table 1: Resistance (2) Voltage (V) At battery Current (A) In circuit Voltage measured across Resistor 0.88 1/R (0) 10 0.88 0.088 1.136 40 0.18 0.0045 0.18 5.555 50 0.17 0.0034 0.17 5.882 80 0.10 0.00125 10 0.10 0.089 100 0.089 0.00089 11.235

3.

Power Rule: P = I × V

If a current I flows through through a given element in your circuit, losing voltage V in the process, then the power dissipated by that circuit element is the product of that current and voltage: P = I × V.

So by increasing current by 4 times results in power increasing by 4 times .

2.

The equation for a straight line is y = mx + b, where m is the slope of the line, and b is the y-intercept

And Ohm's law is V= IR +0

On comparison we see that both are similar with exception of the y intercept in Ohms law .If the resistor obeys Ohm's law, the ratio of the voltage and current remains the same and the graph would be a straight line.The y-axis has the value of voltage (V) and the x-axis has the values of current (I).

i am sorry with the last question as I couldn't understand it well.But if this helped you please like the answer.Thankyou,