Question

Pease answer questions 4 and 5! Thank you so much!



4. Connect the 2nd resistor in parallel with the 1st resistor and connect that combination to the battery.

         Measure the following:

              The current passing through the R1, I1 = ___0.0058____ A

              The current passing through the R2, I2 = ___0.0031____ A

              The current supplied by the battery, I = ___0.0092____ A

             Calculate I1 + I2 = ____________ A

                    Is the following statement true? I = I1 + I2 _____Y or N______

             Calculate the energy delivered by the battery

                                                     = V I = ____________ x ____________

= ___________ Watts

            

Why is the power delivered by the battery greater than in Step 1?  

Answer: __________________________________________________

  __________________________________________________________

  __________________________________________________________

5. Disconnect the battery from the circuit (but leave the two resistors connected in parallel).  

Use the Multimeter to measure the combined resistance of the two resistors connected in parallel:

           Measure the equivalent resistance, R = ___680___ Ohms

           Calculate 1/R, which equals to:

                                          1/R = 1/R1 + 1/R2 = 1/( ) + 1/ ( )

                                                          = __________ + __________

                                                         = ____________

           Calculate R = ____________ Ohms

Is the calculated R and measured R approximately equal to each other?          

____________

For Resistors Connected in Series: In an electric circuit, the equivalent resistance of resistors connected in series is given by the equation: R=R, + R, + R. +..... The power consumed by a resistor = 1R The power delivered by the power source = VI The power delivered by the power source should be equal to the sum of the power consumed by all the resistors. For Resistors Connected in Parallel: In an electric circuit, the equivalent resistance of resistors connected in parallel is given by the equation: 1/R = 1/R, + 1/R, +1/R, + The power consumed by a resistor = 'R The power delivered by the power source = VI The power delivered by the power source should be equal to the sum of the power consumed by all the resistors.

Answer 1

(4) T. +1,= 0.0058 +0.0031 = 0.0089 A Yes I t I, (approximately) VI Energy delivered by battery 6x0.0092 -0.0552 walts Yes, power delivered is maximum in parallel arrangement as equivalent resistance is minimal en parallel arrangement, whereas equivalent resistance in series (Rowerat is matinum ) Req. ㅗ ㅗ + 6) A R Rr 1 + ㅗ ११० 1 2oso YR = 0.00101 +0.0004878 YR = 0.0014979 667.6 ohms. calculated R and measured R affrorimately equal. R yes i are