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A scuba diver exhales 3.32 L of air while swimming at a depth of 20.0 m...

A scuba diver exhales 3.32 L of air while swimming at a depth of 20.0 m where the sum of atmospheric and water pressure is 2.95 atm. By the time the bubbles of air rise to the surface, where the pressure is 1.00 atm, what is their total volume? Assume the temperature of the water body is uniform.
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Answer #1

we can solve this problem by using Boyles law
at constant temperature, volume of gas is inversely proportional to its pressure.
as the pressure drops from 2.95 atm to 1.00 atm , then volume of air raises

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hence volume of air = 9.79 L

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