Question

1. (50 points) Consider the circuit shown below. The resistance Ris 7.00, and 8 = 25v. a. Write the loop equation (Kirchoff's law) for the loop cdefc. b. Write the loop equation for the loop cdeac. c. Solve for the currents 11, 12, and 13. d. What is the current through the ammeter? e. What is the voltage read by the voltmeter? 12.0V 202 HE 8.0 V 7.00 Focus glish (United States) stv AN E

Answer 1

1. 12v 72 d e figi a 250 121 It C + 12v 72 8 V 7n d t c defc loop D 12 C - 7 I +12-8-7 1₂ = 0 f f 7R ov 7 fit7 I2 = 4 for loop edeac -71 +12 -(-2/3) +25-0 =) - FI +2 Iz =-37 For loop cefc -25-2 Iz - 8 - 7 I2 = 0 = 33 . - 7 [2 - 2 I3 from figa using kel at no de e I t Iz - I 2 =0 13 = I2-I.

Now put [3 = 52-6, into ean into ean ④ -71, + 2(12-1) = -37 = -71, +25₂-26 = -37 - 9 I +2 I 2 = -37 I2 = - 37+9 I, 2. NOW put the value of In into ean 75+ 7 (-34 +94) = 4 14 269 + 63 Il = 4 2 776 - 2498 =) 77I, = 25948 267 = 3.47 Amp 77 Fun ean -37 +9 (3.47) I2 = 2 - 2.89 Amp Iz= I2 - Il =-2.89 -3.47 = -6.36 7 I +752 = 4 - 711 +2 I3 = -37 I = 3.47 Amp, I2 = – 2.80 Amp, Iz= – 6.36 Amp current through anometer = I1 = 3.47 Amp