Explaination:
Given equations are:
i1 = i2 + i3 …… (1)
i2 + i3 = i4 …… (2)
i1 R1 + i3 R3 = V1 …… (3)
i1 R1 + i2 R2 = V1 …… (4)
Substitute equation (1) in equation (2), the result is:
i1 = i4 …… (5)
From equation (1), i3 equals,
i3 = i1 – i2 …… (6)
Substitute the values in the equation (3)
10 i1 + 10 i3 = 100
Substitute the equation (6)
Substitute the values of R1, R3, R2, and V1 in the equation (4)
10 i1 + 5 i2 = 100 …… (8)
Convert the equation (7) and (8) in matrix form Ax = b where,
Ax = b form is:
In the MATLAB code, Give the values of A and b. Find the inverse of A and multiply by b. Finally print the desired result of current.
Screenshot of the code:
Sample Output:
Code to copy:
%Substitute the value of A as shown in equation (9).
A = [20 -10;10 5];
%Substitute the value of b as shown in equation (9).
b = [100;100];
% solving using inverse
I = inv(A)*b;
%Print the result i1
fprintf('i1 = %0.2fA \n',I(1));
%Print the result i2
fprintf('i2 = %0.2fA \n',I(2));
%Print the result i3 = i1 - i2 as shown in the
%equation (6)
fprintf('i3 = %0.2fA \n',I(1)-I(2));
%Print the result i4 = i1 as shown in the
%equation (5)
fprintf('i4 = %0.2fA\n',I(1));
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