8. Consider the circuit: t=0 212 f(t)t 222 11 Pilt) 1F yt (a) Show that the...
Find 1.(t) for t>O in the given circuit. 222 + V 12 1F 7.5e-2 V (+ 4.5u(-1) V 0.5v. + 1110 O [1.0714e-2t – 2.572e-t2cos(1.1181) + 4.791e-#2sin(1.1184] (1) A [-1.0714e-2t – 2.572e-t2cos(1.118t) + 4.791e-2sin(1.1181]u(t) A O [1.0714e-2t – 4.791e-t2cos(1.1186) + 2.572e-t2sin(1.1184]u(t) A O [1.0714e-2t + 2.572e-t2cos(1.1181) – 4.791e-t2sin(1.1189],(0) A
Use the differential equation approach to find Vo(t) for t> 0 in the circuit in the figure below 1k0 Please round all numbers to 3 significant digits. Vo(t)
1. Find v(t) fort> 0 in the circuit in below: t=0 222 w 622 w + 10V 2 F +1 50 V Assume the switch has been open for a long time and is closed at t=0.
In the circuit shown below, let C = 1F and v(0−) = 1V. Determine v(t) for t > 0 and sketch it In the circuit shown below, let C-IF and u(0-) = 1 V. Determine v(t) for t > 0 and sketch it. v(t)
In the given circuit, identify (0) and i(t) for t> 0. Assume 10) = 0 V and 1(O) = 2.50 A. + 5u(t) A 222 v+0.5 F ell 1 H [3.780 e-t2cos(1.3229t - 90°)]u(1) V [5 + 2.67252 e-t2cos(1.3229t - 200.79] A [0 – 2.67252e-t2cos(1.3229t – 200.7°)] A [5 – 2.67252e-t/2 cos(1.3229t+ 200.79] A [2.673e-t2cos(1.3229t – 90°)]u(0) V [1.336e-t2 cos(1.3229t+ 90°)]/(t) v
Solve for Iz(t) in the circuit shown for t>O as the switch is closed for t>0. t=0 R3=2000 Rz=2000 Ix V. 24V R; 2009 R2 1000 30 mH
Obtain v(t) for t> 0 in the given circuit. Assume v;= 110 V. F1 F 102 TE The value of v(t) = A cos (Bt + Cu(t) V where A = BOV and C =
Calculate i(t) for t> 0 in the given circuit. Assume A = 35[1 – u(t)] V. + V - 1 F 16 A +1 H 592 The value of i(t) = (A) cos (Ct + Dº)u(t) A where A = C= and D =
Let F be a field of characteristic p > 0. Show that f = t4 +1 € F[t] is not irreducible. Let K be a splitting field of f over F. Determine which finite field F must contain so that K = F.
Please show work! (1 point) Find the Laplace transform F(s) of f(t) { O, t<6 5 sin(at), 6<t<7 0, t> 7 F(8)