Question

PHY 132: Charge to Mass Ratio of the Electron PHY 132: Charge to Mass Ratio of the Electron Constant Voltage If we rearrange Equation 1, we get the following: B - (m/e) x 2v}"2 x (1/r) Set the voltage to 200 V. Set the current so that the path diameter is 5.0 cm. Increase the path diameter in steps of 0.5 cm (by adjusting the current) until it is equal to 8.0 cm. Fill in the values of the current as you go along. In other words, a plot of B vs 1/r has a slope of [(m/e) x 2v1"? Path Diameter (m) Path Radius (m) (Path Diameter/2) 1/ Path Radius (m) Current (A) Current x 7.7 x 10 T/A) For each of these runs, use either Excel or Logger Pro to plot the following: 2.19 o 1/r on the x-axis 0.050 0.055 0.060 0.065 0.070 0.075 0.080 2.03 1.87 1.73 1.6 o B on the y-axis 1.5 1.42 Please show me each graph. Record the values of the slope below. Use the slope to calculate e/m. Increase the voltage to 300 V and repeat: Path Diameter (m) Path Radius (m) 1/Path Radius Current (A) 200 V run: Slope e/m 2V / slope? C/kg B (T) ( Current x 7.7 x 10 T/A) 2.67 300 V run: Slope e/m- 2V / slope. C/kg 0.050 0.055 0.060 0.065 0.070 0.075 0.080 2.49 2.3 2.13 1.97 1.85 1.74 400 V run Slope - e/m- 2V / slope? C/kg Take the average of your e/m values: Increase the voltage to 400 V and repeat: Path Diameter (m) Path Radius (m) 1/Path Radius Current (A) e/m B (T) ( Current x 7.7 x 10T/A) C/kg х X х 2.87 2.65 Compare this value with the theoretical value that you calculated in the prelab: 0.050 0.055 0.060 0.065 0.070 0.075 0.080 2.45 2.28 % difference - [le/m)experimental - (e/m)theoretical/le/m)heoretical ] x 100 % 2.13 1.99

Answer 1

Vo 4G 5:36 AM | 114KB/s Vo 56 socscistatistics.com/tests/ 2 alculator on equation for Yis: = 0.04058X + 0.0785 rom this calculator is fairly verbose. Mostly it should be self-explanatory, but you ent discrepancies in calculations are because rounding is used for the purposes alculations themselves. ther calculation, it is necessary to hit the reset button at the bottom of the page. 1.69- 1.49 Y - Dependent 656 1.29 - 1.095 25 29 33 37 41 X - Independent Regression Line (ỹ = 0.04X + 0.08) Calculation Summary Sum of X= 220.3 Sum of Y= 9.489 Mean X= 31.4714 Mean Y= 1.3556 Sum of squares (SSy) = 174.6535 Sum of products (SP) = 7.0872 Regression Equation = ý = bx + a b = SPISSx = 7.09/174.65 = 0.04058 a = My - bMx = 1.36 - (0.04*31.47) = 0.0785 û = 0.04058X+0.0785 My 0.3304 0.2074 0.0844 -0.0256 -0.1256 -0.2056 -0.2656 (X - My)2 72.7365 23.8981 3.4543 1.2131 8.4183 23.0537 41.8794 (X - Mx)(Y - My) 2.8181 1.014 0.1569 0.0282 0.3643 0.987 1.7186

300V 2.1 1.9 Y- Dependent 1.7 - 1.5 1.31 25 29 33 37 41 X - Independent Regression Line (ỹ = 0.05X +0.13) Calculation Summary Sum of X= 220.3 Sum of Y= 11.67 Mean X= 31.4714 Mean Y= 1.6671 Sum of squares (55x) = 174.6535 Sum of products (SP) = 8.5383 Regression Equation = û = bx + a b = SPISSx = 8.54/174.65 = 0.04889 a = My - bMx = 1.67 - (0.05*31.47) = 0.12859 û = 0.04889X+0.12859

2.3- 400V 2.1 Y- Dependent 1.9 1.7 1.5 25 28 31 34 37 X - Independent Regression Line (j = 0.05% + 0.04) Calculation Summary Sum of X= 180.3 Sum of Y = 11.06 Mean X= 30.05 Mean Y= 1.8433 Sum of squares (SSX) = 89.7942 Sum of products (SP) = 5.3814 Regression Equation = ý = bx + a b = SPISSx= 5.38/89.79 = 0.05993 a= = My - bmx = 1.84 - (0.06*30.05) = 0.04243 û = 0.05993X+ 0.04243

Yoou (1/8) (012) 36-36 33-33 30.77 28,57 26-61 I 2:81 2.65 2.45 2.28 2.13 1.99 B (1x630) 2:21 2.04 1.89 1.75 1.64 1.53 B = 5.99x10 -5 +0.042 at graph gives slope 5,99.X 10 -S elm 2x 2.23 Xio" Islape) 2 Soo Xolo (5.99) 2 akg elm 12.426+2:510 +2.230).X10" 3 Average of sige Angelo 2 2.389 xlo" CIK cityl Thorsen - 1.76 Xto" clky (2:388 - 1-76) Xloo 35.72% ... % erlebte 1.76