Question

Question 46 076 pts Consider the following lines of code aatist = [1, 2, 3, 4, 5, 6) bbrist = 0 echist = 0 for elem in aalist: if elem 20: bbhist.append(elem) mem - aalisti-1] del aalist(-1) cctist = celist + (mem) What does each list contain after the code is created?

Answer 1

Question:
Consider the following lines of code:
aaList=[1,2,3,4,5,6]
bbList=[]
ccList=[]

for elem in aaList:
if elem %2==0:
bbList.append(elem)
mem=aaList[-1];
del aaList[-1]
ccList=ccList+[mem]
What does each list contain after the code is executed:
Ans:
These lists are in the order of aaList then bbList then ccList
[1, 2, 3, 4]   
[2, 4]
[6,5]

First of all, we initialized the aaList and then iterating through the elements in the aaList. if the element is even then we are appending them in bbList and then removing the last element from aaList and then inserting them in ccList.
So, It will append 2,4 elements in bbList since 6 is already deleted which is an even. and the aaList contains only 4 elements which are 1,2,3,4 since 5 and 6 got deleted and ccList contains 2 elements which are 6,5 that are removed from aaList.

Please check the compiled program and its output for your reference:

main.py 1 aalist=[1,2,3,4,5,6] 2 bbList=[] 3 cclist=[] 4 5- for elem in aalist: 6. if elem %2==0: 7 bbList.append(elem) mem=aalist[-1]; 9 del aalist[-1] 10 cclist=cclist+[mem] 11 12 print(aalist) 13 print(bblist), 14 print(cclist) 8

Output:

[1, 2, 3, 4] [2, 4] [6, 5] ... Program finished with exit code o Press ENTER to exit console..

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