Consider the following code snippet. What will be printed by *ptr and ptr after the lines...

Question

Question

Consider the following code snippet. What will be printed by *ptr and ptr after the lines shown. Explain with screenshots.

int a[4] = { 8, 3, 5, 6};

int *ptr = a;

ptr ++;

Answer 1

Answer #1

Code Snippet

   int a[4] = { 8, 3, 5, 6};
   int *ptr = a;
   ptr ++;

Break-down

int a[4] = {8, 3, 5, 6}; // array a is holding set of integers.

int *ptr = a; // pointer ptr is containing the value of a (base address of array a).

ptr ++; // pointer pts is incremented to its next position in array.

Output

The ptr will first print the base address of the array, if used with * operator (like *ptr) it will print the value at first position in array i.e 8.

After incrementing it is moved one step ahead and it will print next value in the array i.e 3.

Answer 2

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