Your IP and mask are 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?
Answer-
since 255.255.255.248.
in fourth octet 2^8=256
248 has block size of 8/ so subsets are 0,8,16,24,32,64
here 10 will be in between 8 and 16. so the broadcast address will be 15.
Your IP and mask are 192.168.192.10/29. What is the broadcast address the hosts will use on...
using the information given below
. what is the ip address , subnet mask , default gateway?
** corrections
# of bits in subnet for A
:6
# of bits in submet for B:
3
PC-A
R1 G0/0
R GO/1
S1
PC-B ?
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