IP address: 158.234.28.72 Subnet Mask: 255.248.0.0 Find Network Address and Broadcast address. Provide all necessary steps.
IP Address: 158.234.28.72 ---------------------------------------- Let's first convert this into binary format 158.234.28.72 Let's convert all octets to binary separately Converting 158 to binary Divide 158 successively by 2 until the quotient is 0 158/2 = 79, remainder is 0 79/2 = 39, remainder is 1 39/2 = 19, remainder is 1 19/2 = 9, remainder is 1 9/2 = 4, remainder is 1 4/2 = 2, remainder is 0 2/2 = 1, remainder is 0 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 10011110 158 in binary is 10011110 Converting 234 to binary Divide 234 successively by 2 until the quotient is 0 234/2 = 117, remainder is 0 117/2 = 58, remainder is 1 58/2 = 29, remainder is 0 29/2 = 14, remainder is 1 14/2 = 7, remainder is 0 7/2 = 3, remainder is 1 3/2 = 1, remainder is 1 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 11101010 234 in binary is 11101010 Converting 28 to binary Divide 28 successively by 2 until the quotient is 0 28/2 = 14, remainder is 0 14/2 = 7, remainder is 0 7/2 = 3, remainder is 1 3/2 = 1, remainder is 1 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 11100 28 in binary is 00011100 Converting 72 to binary Divide 72 successively by 2 until the quotient is 0 72/2 = 36, remainder is 0 36/2 = 18, remainder is 0 18/2 = 9, remainder is 0 9/2 = 4, remainder is 1 4/2 = 2, remainder is 0 2/2 = 1, remainder is 0 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 1001000 72 in binary is 01001000 ==================================================================================== || 158.234.28.72 in binary notation is 10011110.11101010.00011100.01001000 || ==================================================================================== Subnet address: 255.248.0.0 ---------------------------------------- Let's convert this into binary format 255.248.0.0 Let's convert all octets to binary separately Converting 255 to binary Divide 255 successively by 2 until the quotient is 0 255/2 = 127, remainder is 1 127/2 = 63, remainder is 1 63/2 = 31, remainder is 1 31/2 = 15, remainder is 1 15/2 = 7, remainder is 1 7/2 = 3, remainder is 1 3/2 = 1, remainder is 1 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 11111111 255 in binary is 11111111 Converting 248 to binary Divide 248 successively by 2 until the quotient is 0 248/2 = 124, remainder is 0 124/2 = 62, remainder is 0 62/2 = 31, remainder is 0 31/2 = 15, remainder is 1 15/2 = 7, remainder is 1 7/2 = 3, remainder is 1 3/2 = 1, remainder is 1 1/2 = 0, remainder is 1 Read remainders from the bottom to top as 11111000 248 in binary is 11111000 Converting 0 to binary Divide 0 successively by 2 until the quotient is 0 Read remainders from the bottom to top as 0 in binary is 00000000 Converting 0 to binary Divide 0 successively by 2 until the quotient is 0 Read remainders from the bottom to top as 0 in binary is 00000000 ================================================================================== || 255.248.0.0 in binary notation is 11111111.11111000.00000000.00000000 || ================================================================================== Remove all dots to form 11111111111110000000000000000000 Remove all 0's from the right side to form 1111111111111 Number of 1's in this is 13 so, Subnet mask is /13 For Calculating network ID, keep first 13 bits of 10011110.11101010.00011100.01001000 and set all remaining bits to 0. so, network ID in binary is 10011110.11101000.00000000.00000000 10011110.11101000.00000000.00000000: ---------------------------------------- 10011110.11101000.00000000.00000000 Let's convert all octets to decimal separately Converting 10011110 to decimal => 10011110 => 1x2^7+0x2^6+0x2^5+1x2^4+1x2^3+1x2^2+1x2^1+0x2^0 => 1x128+0x64+0x32+1x16+1x8+1x4+1x2+0x1 => 128+0+0+16+8+4+2+0 => 158 10011110 in decimal is 158 Converting 11101000 to decimal => 11101000 => 1x2^7+1x2^6+1x2^5+0x2^4+1x2^3+0x2^2+0x2^1+0x2^0 => 1x128+1x64+1x32+0x16+1x8+0x4+0x2+0x1 => 128+64+32+0+8+0+0+0 => 232 11101000 in decimal is 232 Converting 00000000 to decimal => 00000000 => 0x2^7+0x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0 => 0x128+0x64+0x32+0x16+0x8+0x4+0x2+0x1 => 0+0+0+0+0+0+0+0 => 0 00000000 in decimal is 0 Converting 00000000 to decimal => 00000000 => 0x2^7+0x2^6+0x2^5+0x2^4+0x2^3+0x2^2+0x2^1+0x2^0 => 0x128+0x64+0x32+0x16+0x8+0x4+0x2+0x1 => 0+0+0+0+0+0+0+0 => 0 00000000 in decimal is 0 =================================================================================== || 10011110.11101000.00000000.00000000 in decimal notation is 158.232.0.0 || =================================================================================== ========================================== || So, Network ID is 158.232.0.0 || ========================================== For Calculating broadcast ID, keep first 13 bits of 10011110.11101010.00011100.01001000 and set all remaining bits to 1. so, broadcast ID in binary is 10011110.11101111.11111111.11111111 10011110.11101111.11111111.11111111: ---------------------------------------- 10011110.11101111.11111111.11111111 Let's convert all octets to decimal separately Converting 10011110 to decimal => 10011110 => 1x2^7+0x2^6+0x2^5+1x2^4+1x2^3+1x2^2+1x2^1+0x2^0 => 1x128+0x64+0x32+1x16+1x8+1x4+1x2+0x1 => 128+0+0+16+8+4+2+0 => 158 10011110 in decimal is 158 Converting 11101111 to decimal => 11101111 => 1x2^7+1x2^6+1x2^5+0x2^4+1x2^3+1x2^2+1x2^1+1x2^0 => 1x128+1x64+1x32+0x16+1x8+1x4+1x2+1x1 => 128+64+32+0+8+4+2+1 => 239 11101111 in decimal is 239 Converting 11111111 to decimal => 11111111 => 1x2^7+1x2^6+1x2^5+1x2^4+1x2^3+1x2^2+1x2^1+1x2^0 => 1x128+1x64+1x32+1x16+1x8+1x4+1x2+1x1 => 128+64+32+16+8+4+2+1 => 255 11111111 in decimal is 255 Converting 11111111 to decimal => 11111111 => 1x2^7+1x2^6+1x2^5+1x2^4+1x2^3+1x2^2+1x2^1+1x2^0 => 1x128+1x64+1x32+1x16+1x8+1x4+1x2+1x1 => 128+64+32+16+8+4+2+1 => 255 11111111 in decimal is 255 ======================================================================================= || 10011110.11101111.11111111.11111111 in decimal notation is 158.239.255.255 || ======================================================================================= ================================================ || So, broadcast ID is 158.239.255.255 || ================================================
IP address: 158.234.28.72 Subnet Mask: 255.248.0.0 Find Network Address and Broadcast address. Provide all necessary steps.
Type or paste question here IP Address: 192.144.96.0 Subnet Mask: 255.255.240.0 find Network address, Broadcast address, first valid host address, last valid host address and number of valid hosts in the network. show very clear steps for all the calculations.
Given the following IP address and subnet mask, what is the network identifier? • IP Address: 18.132.219.175 . Subnet Mask: 255.255.248.0 Network ID: BLANK-1 BLANK-1 Add your answer Question 28 Given the following IP address and subnet mask, what is the network identifier? - IP Address: 18.132.219.175 . Subnet Mask: 255.255.248.0 • Broadcast Address: BLANK-1 BLANK-1 Add your answer
Network Subnetting 3 1. Given an IP address of 210.21.21.21 and a subnet mask of 255.255.252.0, what is the address of the network? And the broadcast address? Show your calculation. 2. On a network with an IP address of 155.155.155.155 and a subnet mask of 255.255. 248.0 what is the network ID? And the broadcast address? Show your calculation.
Which of the following is the purpose of a subnet mask in a network? (Select all that apply) a. A subnet mask is not necessary when a default gateway is specified. b. A subnet mask is used to differentiate between the network address, the host addresses, and the broadcast address. c. A subnet mask is required only when bits are borrowed on a network. d. A subnet mask is used to determine in which subnet an IP address belongs. e....
Network IP Addressing Network Layout of 2 networks Given an IP address and mask of 172.23.29.0/24, design an IP addressing scheme that satisfies the following requirements. Subnet B Specification This network requires space for 62 machines plus the router Number of bits in the subnet Blank 1 IP mask (binary) Blank 2 New IP mask (decimal) Blank 3 Maximum number of usable subnets of this size when using this mask (including the 0th subnet) Blank 4 Number of usable hosts...
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(a) What is the network number of the IP address 140.100.120.02 if the subnet mask is 255.255.224.0? (b) Does it make sense to have a subnet mask equal to 255.255.224.7? why or why not? (c) Suppose an organization needs 8000 IP addresses. How many Class C addresses would be needed? If they were consecutive, describe the CIDR addressing scheme.
What is the broadcast address of the network with a host address of 10.128.64.27 and subnet mask 255.255.255.248? (1 + 3 marks) Correct answer is worth 1 mark (answer format would be an IP address, such as: 192.168.1.1) Showing your work to arrive at the solution is worth 3 marks. Please submit your work in the dropbox.
2. Given the IP address 17.119.47.72, apply Subnet Mask 1 and answer the following questions. [2 marks] My subnet mask is: a. What is the subnet address? b. What is the broadcast address for this subnet? Given the IP address 17.119.47.72, apply Subnet Mask 1 and answer the following questions. [2 marks] My subnet mask is: 255.240.0.0 a. What is the subnet address? * What is the broadcast address for this subnet?
Given an IP address and mask of 192.168.1.0 255.255.255.0 (address / mask) subnet A has 55 hosts subnet b has 112 hosts The 0th subnet is not used. (Do not use 192.168.1.0) (Subnetting Help) Subnet A Specification Student Input Number of Network bits in the subnet mask New Subnet mask (decimal) Number of usable hosts IP Subnet (Network ID) First IP Host address Last IP Host address (Subnetting Help) Subnet B Specification Student Input Number of Network bits in the...