Question

Consider the circult shown in the given figure. Assume - 60 Hz Vs - 7020 Vrms, R-18 ohm. C-50 pF, and L - 0.001 H. References eBook & Resources Section Break Problem 07031 value 5.00 points You did not Problem 07.031.a Calculate the apparent power supplied by the voltage source. (Round the final answer to two decimal places.) The apparent power supplied by the voltage source is 732 VA

Answer 1

Answer-7.031 a

   Given,

   f = 60 Hz

   $\small \tilde{V_{s}}=70\angle 0^{\circ}Vrms$

   R = 18 ohm

   C = 50 $\small \mu$ F

   L = 0.001 H

So,

   $\small X_{L}=\omega L=2\pi fL=2\pi \times 60\times 0.001=0.377\Omega$

   $\small X_{C}=\frac{1}{\omega C}=\frac{1}{2\pi fC}=\frac{1}{2\pi \times 60\times 50\times 10^{-6}}=53.05\Omega$

So,

   $\small Z=R+jX_{L}-jX_{c}$

  $\small Z=18+j0.377-j53.05$

   $\small Z=18-j52.673$

The apparent power supplied by the source is,

     $\small S=\frac{\tilde{V_{s}}^{2}}{\left | Z \right |}$

$\small S=\frac{(70)^{2}}{\sqrt{(18)^{2}+(52.673)^{2}}}$

S = 88.03 VA