SInce we have to prove till 8 that the base step is true so (1):8
and then we have to show that its true for s(k+1) when it was true for s(k)
so the answer is
(1):8
(2):S(k+1)
Let S(n) be a statement parameterized by a positive integer n. Consider a proof that uses...
4. Let P(n) be the statement that a postage of n cents can be formed using just 4-cent stamps and 7-cent stamps. The parts of this exercise outline a strong induction proof that P (n) is true forn > 18. a) Show statements P(18), P(19), P (20), and P(21) are true, completing the basis step of the proof. b) What is the inductive hypothesis of the proof? c) What do you need to prove in the inductive step? d) Complete...
3. Let P(n) be the statement that a postage of n cents can be formed using just 3-cent stamps and 5-cent stamps. The 5 / Induction and Recursion parts of this exercise outline a strong induction proof that P(n) is true for n 18. a) Show statements P(18), P(19), P(20), and P(21) are true, completing the basis step of the proof. b) What is the inductive hypothesis of the proof? c) What do you need to prove in the inductive...
Use mathematical induction to prove that the statement is true for every positive integer n. 1'3+ 24 +3'5 +...+() = (n (n+1)(2n+7))/6 a. Define the last term denoted by t) in left hand side equation. (5 pts) b. Define and prove basis step. 3 pts c. Define inductive hypothesis (2 pts) d. Show inductive proof for pik 1) (10 pts)
3 For each positive integer n, define E(n) 2+4++2n (a) Give a recursive definition for E(n). (b) Let P(n) be the statement E(n) nn1)." Complete the steps below to give a proof by induction that P(n) holds for every neZ+ i. Verify P(1) is true. (This is the base step.) ii. Let k be some positive integer. We assume P(k) is true. What exactly are we assuming is true? (This is the inductive hypothesis.) iii. What is the statement P(k...
11: I can identify the predicate being used in a proof by mathematical induction and use it to set up a framework of assumptions and conclusions for an induction proof. Below are three statements that can be proven by induction. You do not need to prove these statements! For each one clearly state the predicate involved; state what you would need to prove in the base case; clearly state the induction hypothesis in terms of the language of the proposition...
Problem 1 148pts] (1) I 10pts! Let P(n) be the statement that l + 2 + + n n(n + 1) / 2 , for every positive integer n. Answer the following (as part of a proof by (weak) mathematical induction): 1. [2pts] Define the statement P(1) 2. [2pts] Show that P(1 is True, completing the basis step. 3. [4pts] Show that if P(k) is True then P(k+1 is also True for k1, completing the induction step. [2pts] Explain why...
50. What is wrong with this "proof? "Theorem For every positive integer n = (n + /2. Basis Step: The formula is true for n = 1. Inductive Step: Suppose that +Y/2. Then -(+972 +*+- +*+1)/2 + + + /- + 1). By the inductive hypothesis, we have + /2-[(++P/2, completing the + inductive step.
In the following problem, we will work through a proof of an important theorem of arithmetic. Your job will be to read the proof carefully and answer some questions about the argument. Theorem (The Division Algorithm). For any integer n ≥ 0, and for any positive integer m, there exist integers d and r such that n = dm + r and 0 ≤ r < m. Proof: (By strong induction on the variable n.) Let m be an arbitrary...
Match the following: item 1. Indirect proof which assumes the opposite of a statement and shows this creates a logical inconsistency item 2, Indirect proof applied to a statement of the form P→Q which instead proves-Q→-P. item 3. Proves a "there exists" statement by finding a specific element for which the statement is true item 4. Disproves a "for all" statement by finding a specific element for which the statement is false. item 5. Proof where a statement is split...
(3) Uee mathematical induction to prove that the statement Vne ZtXR<n) → (2n+/< 2")) is true. (Suggestion : Let Ple) dernote the sentence "(2<n)-> (21+k< 20)". In carrying out the proof of the inductive step Van Zyl onafhan) consider the cases PQ)=P(2), P2)->P(3), and Pn>Plitr) for 173, Separately.)